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3 years ago

13

URGENT PHYSIC PLEASE.

1 answer:

KonstantinChe [14]3 years ago

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Thanks eBay raids rugs idc

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Which example is a physical change?

Degger [83]

Answer: a change from one state of matter to another

Explanation: Phase change is an example of a physical change. The chemical composition does not alter during phase change. For example when ice melts its composition is still H2O but in liquid form.

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4 years ago

A Ferris wheel has radius 5.0 m and makes one revolution every 8.0 s with uniform rotation. A person who normally weighs 670 N i

DaniilM [7]

Answer:

The apparent weight of the person as she pass the highest point is $N = 458.8 \ N$

Explanation:

From the question we are told that

The radius of the Ferris wheel is $r = 5.0 \ m$

The period of revolution is $T = 8.0 \ s$

The weight of the person is $W = 670 \ N$

Generally the speed of the wheel is mathematically represented as

$v = \frac{2 \pi r}{T }$

substituting values

$v = \frac{2 * 3.142 * 5}{8 }$

$v = 3.9 3 \ m/s$

The apparent weight (the normal force exerted on her by the bench) at the highest point is mathematically evaluated as

$N = mg - \frac{mv^2}{r}$

Where m is the mass of the person which is mathematically evaluated as

$m = \frac{W}{g}$

substituting values

$m = \frac{670}{9.8}$

$m = 68.37 \ kg$

So

$N = 68.37 * 9.8 - \frac{68.37 * {3.93}^2}{5}$

$N = 458.8 \ N$

5 0

3 years ago

What does the vibrating object do to the air particles around it ?

dimulka [17.4K]

Answer:

When an object vibrates, it causes the molecules in the air around it to move. These molecules collide with nearby molecules, forcing them to vibrate as well. As a result, they collide with more surrounding air molecules.

Explanation:

3 0

3 years ago

If you are pushing an object to the left, which way is the friction force acting?

AleksandrR [38]

To the right, if you push something left the friction is to the right

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3 years ago

Read 2 more answers

In April 1974, Steve Prefontaine completed a 10 km race in a time of 27 min, 43.6 s. Suppose "Pre" was at the 8.13 km mark at a

SOVA2 [1]

Answer: $0.084 m/s^2$

Explanation:

Given

Total time=27 min 43.6 s=1663.6 s

total distance=10 km

Initial distance $d_1=8.13 km$

time taken=25 min =1500 s

initial speed $v_1=\frac{8.13\times 1000}{25\times 60}=5.6 m/s$

after 8.13 km mark steve started to accelerate

speed after 60 s

$v_2=v_1+at$

$v_2=5.6+a\times 60$

distance traveled in 60 sec

$d_2=v_1\times 60+\frac{a60^2}{2}$

$d_2=336+1800 a$

time taken in last part of journey

$t_3=1663.6-1560=103.6 s$

distance traveled in this time

$d_3=v_2\times t_3$

$d_3=\left ( 5.6+a\times 60\right )103.6$

and total distance $=d_1+d_2+d_3$

$10000=8.13\times 1000+336+1800 a+\left ( 5.6+a\times 60\right )103.6$

$1870=336+1800 a+\left ( 5.6+a\times 60\right )103.6$

$a=0.084 m/s^2$

5 0

4 years ago