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ozzi
2 years ago
10

How should you draw the field lines for Earth's magnetic field?

Physics
2 answers:
Juliette [100K]2 years ago
7 0

Answer:

Coming out near the South Pole and going in near the North Pole

Explanation:

yuradex [85]2 years ago
3 0
A. Coming out near the South Pole and going in near the North Pole
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9. A body is a particular amount of matter. It can be a solid, liquid or gas. It can be
soldier1979 [14.2K]

Answer:

B. Time and Space

Explanation:

Matter is a pshyical or corporeal susbtance in general, whether solid, liquid, or gaseous especially as distinguised from incorpeal substance, as spirit or mind, or form qualities, actions, and the

Within this time-and-space boundary, all matter exists. All matter is made up of atoms. Because these atoms take up space in the universe, solids, liquids, and gases are recognized as existing and may be found in all three dimensions.

Time is a figurative term. Space has three dimensions but time only has one.

7 0
2 years ago
Read 2 more answers
How much do a steel BB weight?
pychu [463]
Each BB 0.349 grams and 5.386 grains. 349 mg & 5.386 grains each steel BBs.
6 0
2 years ago
A proton is initially moving west at a speed of 1.10 106 m/s in a uniform magnetic field of magnitude 0.281 T directed verticall
kifflom [539]

Answer:

so here it will move in circle with radius 4.06 cm

Explanation:

As we know that proton is moving towards west while the magnetic field is vertically upwards

So here the force on the proton must be perpendicular to the velocity

So here we have

F = q(\vec v \times \vec B)

so here we have

F = qvB sin90

since force is perpendicular to the velocity so here it must be centripetal force

here we have

\frac{mv^2}{R} = qvB

so we have

R = \frac{mv}{qB}

R = \frac{(1.66 \times 10^{-27})(1.10 \times 10^6)}{(1.6 \times 10^{-19})(0.281)}

R = 4.06 cm

so here it will move in circle with radius 4.06 cm

8 0
2 years ago
I NEED some help please!
andrew11 [14]
Fhfjhfjikauijpoejfdjkkjff\

3 0
3 years ago
At the end of the Shock Wave roller coaster ride, the 6000-kg train of cars (includes passengers) is allowed from a speed of 20
Angelina_Jolie [31]

Answer:

56250 N

Explanation:

mass, m = 6000 kg

initial speed, u = 20 m/s

final speed, v = 5 m/s

distance, s = 20 m

Use third equation of motion

v^{2}=u^{2}+2as

5 x 5 = 20 x 20 + 2 a x 20

25 = 400 + 40 a

a = - 9.375 m/s^2

Braking force, F = mass x acceleration

F = 6000 x 9.375

F = 56250 N

6 0
3 years ago
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