Answer:
A. The particles will begin to move enough
that they slide past each other.
Explanation:
When the plastic cup is heated, the Kinetic energy of its particles starts increasing. As the temperature rises, the kinetic energy keeps increasing. With the increase of K.E, the particles start moving faster and faster. When the temperature finally reaches the melting point, the K.E of the molecules is enough to break the bonds and slide past each other.
Answer:
so the speed will increase by 1.44 times then the initial speed if the distance is increased to double
Explanation:
As we know that the air friction or resistance due to air is neglected then we can use the equation of kinematics here
since we released it from rest so we have
so here we have
now if the distance is double then we have
now from above two equations we can say that
so the speed will increase by 1.44 times then the initial speed if the distance is increased to double
<span>A boat would
produce the highest concentration of carbon monoxide in the exhaust system.
</span>Carbon monoxide<span> (CO) is a colorless, odorless, and tasteless gas that is
slightly less dense than air. It is toxic to </span>hemoglobic<span> <span>animals (both </span></span>invertebrate<span> <span>and
vertebrate, including humans) when encountered in concentrations above about 35 </span></span>ppm<span>.</span>
Answer:
The second vector 
points due West with a magnitude of 600N
Explanation:
The original vector 
points with a magnitude of 200N due east, the Resultant vector 
points due west (that's how east/west direction can be interpreted, from east to west) with a magnitude of 400N. If we choose East as the positive direction and West as the negative one, we can write the following vectorial equation:
With the negative sign signifying that the vector points west.
Answer:
a) -41.1 Joule
b) 108.38 Kelvin
Explanation:
Pressure = P = 290 Pa
Initial volume of gas = V₁ = 0.62 m³
Final volume of gas = V₂ = 0.21 m³
Initial temperature of gas = T₁ = 320 K
Heat loss = Q = -160 J
Work done = PΔV
⇒Work done = 290×(0.21-0.62)
⇒Work done = -118.9 J
a) Change in internal energy = Heat - Work
ΔU = -160 -(-118.9)
⇒ΔU = -41.1 J
∴ Change in internal energy is -41.1 J
b) V₁/V₂ = T₁/T₂
⇒T₂ = T₁V₂/V₁
⇒T₂ = 320×0.21/0.62
⇒T₂ = 108.38 K
∴ Final temperature of the gas is 108.38 Kelvin
