What is the first step for both loading and unloading a firearm?

A 200-foot tall monument is located in the distance. From a window in a building, a person determines that the angle of elevatio

egoroff_w [7]

Answer:

665 ft

Explanation:

Let d be the distance from the person to the monument. Note that d is perpendicular to the monument and would make 2 triangles with the monuments, 1 up and 1 down.

The side length of the up right-triangle knowing the other side is d and the angle of elevation is 13 degrees is

$dtan13^0 = 0.231d$

Similarly, the side length of the down right-triangle knowing the other side is d and the angle of depression is 4 degrees

$dtan4^0 = 0.07d$

Since the 2 sides length above make up the 200 foot monument, their total length is

0.231d + 0.07d = 200

0.301 d = 200

d = 200 / 0.301 = 665 ft

7 0

3 years ago

Which are examples of convection currents ? Select three options.

Veseljchak [2.6K]

<u>Answer</u>:

(B) A pot being heated by an electric burner

(D) A radiator that emits warm air and draws in cool air

(E) A hot air balloon rising and falling in the atmosphere

These are some of the examples of the convection currents.

<u>Explanation</u>:

Earlier, electrons were believed to have positive charges and then electric current were discovered. But later after the invention of electric current and current which is termed to be the flow of electrons and is usually flows from negative to positive terminal. But its convention is not discarded in which current moves from positive terminal to negative and it is called convention current. The direction of current shown in the circuit is said to be the convention current.

Hence, the following are the examples of convention current.

1. Boiling water - The energy travels into the pot from the burner, boiling down the water. Then this warm water is accumulating on the top and colder one is heading down to absorb it, triggering a circular motion.

2. Radiator - Place hot air at the peak and pull cool air at the bottom.

3. Hot air balloon - The air is warmed up by a heating element within the balloon, so the air jumps upwards. This induces the balloon to increase in size due to the inside trapping of the warm air. He removes a few of the warm air when the pilot commences to dive, and cold air takes place, enabling the parachute to drop.

3 0

3 years ago

Read 2 more answers

A torque of 4 Nm is required to rotate the intermediate cylinder at 30 radians/min. Calculate the viscosity of the oil. All cyli

NISA [10]

Answer: viscosity of the oil becomes μ = 0.2003 pa.s

Explanation:

from the given question, we have that

torque T = 4Nm

height H = 450mm = 0.45m

rotational speed ω = 30rpm = 30×2π/60 = 3.14 rad/sec

also to calculate for the linear velocity of the intermediate cylinder,

V = Rω

where R is the radius of the cylinder.

now we substitute values of R and ω, we have

V = Rω

V = 0.15 × 3.14 = 0.471 m/s

calculating the drag force on the two side of the cylinder;

Fd = 2μA (Δv/Δy)

Fd = 2μA V/h

where A = 2πRH

Fd = 2μ(2πRH) V/h

h = thickness, μ = viscosity of oil, H = height of cylinder, and V = mean velocity of cylinder

substituting values we have,

Fd = 2μ * (2π*0.15*0.45)* 0.471/0.003

Fd = 133.10μN

from the torque equation, we can calculate the viscosity

thus, T = Fd*R

we already have Fd = 133.10μN, substituting it into the above expression we have

T = 133.10μ * 0.15 where T is 4Nm,

∴ μ = 4/ 133.1*0.15

μ = 0.2003 pa.s

i hope this helps, cheers

6 0

3 years ago

A certain fan is capable of using 4800J of electrical energy each minute, converting 4000J of it into kinetic energy of the fan.

lapo4ka [179]

Answer:

Energy Ouput (Useful) / Total Energy Input = 4000 / 4800 = .833

E = 83% assuming 4800 is actually input to fan

8 0

2 years ago

If a gun is sighted to hit targets that are at the same height as the gun and 95 m away, how low will the bullet hit if aimed di

Elina [12.6K]

Horizontal distance between the bullet and the target (s) = 195 m

Horizontal velocity of the bullet (u) = 275 m/s

Time taken to cover the horizontal distance = $\frac{Distance}{velocity}$

Time taken (t) = $\frac{195}{275}$

t = 0.709 s

Now, in the vertical direction:

Initial velocity (u) = 0 m/s

Let the depth covered be h.

Time taken (T) = 0.709 s

Acceleration due to gravity (g) = 9.8 m/s^2

Now, using the seconds equation of motion:

$h = ut + \frac{1}{2}at^2$

$h = 0 +\frac{1}{2}\times 9.8 \times 0.709^2$

h = 2.463 meters

Hence, the bullet will hit 2.463 meters below the target.

3 0

3 years ago