2 years ago

Two ice skaters are at rest, Abby

Physics

2 answers:

nikdorinn [45]2 years ago

8 0

Answer:68.4kg

Explanation:

alekssr [168]2 years ago

6 0

Answer:

This is the answer

Explanation:

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kumpel [21]

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It is given that,

Wavelength of monochromatic light, $\lambda=600\ nm=6\times 10^{-7}\ m$

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(a) We need to find the angle corresponding to the first bright fringe. For bright fringe the equation is given as :

$d\ sin\theta=n\lambda$ , n = 1

$\theta=sin^{-1}(\dfrac{\lambda}{d})$

$\theta=sin^{-1}(\dfrac{6\times 10^{-7}}{2.2\times 10^{-5}})$

$\theta=1.56^{\circ}$

(b) We need to find the angle corresponding to the second dark fringe, n = 1

So, $d\ sin\theta=(n+\dfrac{1}{2})\lambda$

$sin\theta=\dfrac{3\lambda}{2d}$

$\theta=sin^{-1}(\dfrac{3\lambda}{2d})$

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