The body moves at a velocity of 1.62m/s after the bullet emerges.
<h3>Given:</h3>
Mass of bullet, 
= 22g
= 0.022 kg
Mass of the block, 
= 1.9 kg
Velocity of bullet , 
= 265 m/s
According to the law of collision which states that the momentum of the body before the collision is equal to the momentum of the body after the collision.
After penetration;
The formula for calculating the collision of a body is expressed as:
p = mv
m is the mass of the body
v is the velocity of the body
∴ Momentum before = Momentum after
Substitute the given parameters into the formula as shown:
Therefore, It moves with a velocity of 1.62 m/s.
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Answer:
A=60.06 x 10⁻⁵ m²
Explanation:
Given that
Weight of the person = 864 N
Weight of the bike = 85 N
The total weight ,car + bike ,Wt= 864 + 85 N
Wt = 949 N
2 p = 949 N
The weight on the each tire(F) = 474.5 N
P = 7.9 x 10 ⁵ Pa
We know that
Force = Pressure x Area
F= P A
By putting the values
474.5 = 7.9 x 10 ⁵ A
A=60.06 x 10⁻⁵ m²
Therefore area of contact A
A=60.06 x 10⁻⁵ m²
Explanation:
<h3>The beam balance is a device used</h3><h3> for the determination of the mass of </h3><h3>a body under gravitation. It consists </h3><h3>of a beam supported at the centre </h3><h3>by an agate knife edge resting on a</h3><h3> support moving inside a vertical </h3><h3>pillar. The beam carries a light</h3><h3>pointer which moves over a scale.</h3>
Condensation is a change of state from vapour to liquid while
freezing is also a change of state, from liquid to solid. Both are
change of states.
Additionally, condensation requires
much more energy to change the state of vapor to liquid than it does it
change the state of liquid to solid.
The internal energy of the gas after the adiabatic compression will be 30.398 × 10⁶ J
<h3>What is work done by gas?</h3>
When energy is moved from one store to another, work is completed. Work done on the gas is taken as -ve.
Given data;
pressure(P)=3.0 atm = 303975 N/m²
The initial volume, V₁
work is done on the gas., W=?(-ve)
Change in heat, ΔQ=0
Change in the internal energy of the gas., ΔE
The work done on the gas;
W = -PΔV
W= - 303975 N/m² × 100 cm³
W = - 30.3 × 10⁶ J
The internal energy is found as;
ΔE=q+w
ΔE= 0-30.3 × 10⁶ J
ΔE= -30.3 × 10⁶ J
E₂-E₁= -30.3 × 10⁶ J
E₂ = -30.3 × 10⁶ J +500
E₂ = 30.398 × 10⁶ J
Hence, the internal energy of the gas after the adiabatic compression will be 30.398 × 10⁶ J
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