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AysviL [449]
3 years ago
5

What is the result when the number 10 is increased by 3%?

Mathematics
1 answer:
Monica [59]3 years ago
6 0
So if we are increasing a number, we are increasing its percentage value. The normal percentage value for an item is 100% or 1. We can take 3% and turn it into a decimal.
3% is the same as 0.03 as a decimal. The next step is to add 0.03+1 .00 to get 1.03. We have to always add the 1.00 whenever we are increasing the value. I’ll give you a reason why, let’s say you want to buy a skateboard and there are no sales so that you can get it for cheaper. The price will always be 1.00% no matter what.
So lastly we have to multiply 1.03 by 10

Which will give us 10.30

Please give me brainliest or give me a heart. Contact me on Instagram if you need more help.
@jessmyybest
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Valerie deposited $2000 into an IRA that grew to $5000 by retirement. If Valerie is currently in the 15% tax bracket and retired
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The answer will be $750
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Given: -1/2x>6. Choose the solution set
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Answer:

B

Step-by-step explanation:

multiply both sides by 2 to eliminate the fraction

- x > 12

multiply both sides by - 1

Remembering to reverse the inequality symbol as a consequence

x < - 12 ← reverse symbol

⇒ { x | x ∈ R, x < - 12 } → B


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3 years ago
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Two different simple random samples are drawn from two different populations. The first sample consists of 30 people with 16 hav
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Answer:

  • There is no significant evidence that p1 is different than p2 at 0.01 significance level.
  • 99% confidence interval for p1-p2 is  -0.171 ±0.237 that is (−0.408, 0.066)

Step-by-step explanation:

Let p1 be the proportion of the common attribute in population1

And p2 be the proportion of the same common attribute in population2

H_{0}: p1-p2=0

H_{a}: p1-p2≠0

Test statistic can be found using the equation:

z=\frac{p2-p1}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 is the sample proportion of the common attribute in population1 (\frac{16}{30} =0.533)
  • p2 is the sample proportion of the common attribute in population2 (\frac{1337}{1900} =0.704)
  • p is the pool proportion of p1 and p2 (\frac{16+1337}{30+1900}=0.701)
  • n1 is the sample size of the people from population1 (30)
  • n2 is the sample size of the people from population2 (1900)

Then z=\frac{0.704-0.533}{\sqrt{{0.701*0.299*(\frac{1}{30} +\frac{1}{1900}) }}} ≈ 2.03

p-value of the test statistic is  0.042>0.01, therefore we fail to reject the null hypothesis. There is no significant evidence that p1 is different than p2.

99% confidence interval estimate for p1-p2 can be calculated using the equation

p1-p2±z*\sqrt{\frac{p1*(1-p1)}{n1}+\frac{p2*(1-p2)}{n2}} where

  • z is the z-statistic for the 99% confidence (2.58)

Thus 99% confidence interval is

0.533-0.704±2.58*\sqrt{\frac{0.533*0.467}{30}+\frac{0.704*0.296}{1900}} ≈ -0.171 ±0.237 that is (−0.408, 0.066)

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3 years ago
Round each amount to the nearest hundred to find the estimate of 9635 - 4891
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ASAP HELP:The number of chapters read, y, after x days. The 5 slope of the line is and the y-intercept is 2. slope means... y-in
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Answer:

Step-by-step explanation:

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Number of days spent to read = x

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For slope = 1.25 means "1.25 pages read per day"

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y-intercept = 2 means "2 pages have been already read"

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