2.48 grams.
<h3>Explanation</h3>
Start by finding the formula mass for cobalt (II) chloride and cobalt (II) chloride hexahydrate.
As a transition element in the middle d-block of the periodic table, cobalt can form ions with a plurality of charges. It is thus necessary to indicate its charge in systematic names of cobalt-containing formula.
The cation "cobalt" in the systematic name of the salt has the Roman numeral "(II)" attached to it in brackets. As a metal, cobalt forms positively-charged ion. The one here thu has charge of +2.
Chloride ions have charges -1. Charges cancel out to produce neutral compounds. Each cobalt cation in this salt would thus pair with two chloride anions. Hence the empirical formula: .
The prefix "<em>hexa-</em>" in the name cobalt (II) chloride <em>hexa</em>hydrate indicates that every formula unit of this salt contains six units of water. The hydrated salt thus has an empirical formula of .
Given the relative atomic mass for each of the elements, as seen on a modern periodic table of the elements:
- Cobalt- 58.93
- Chloride- 35.45
- Hydrogen- 1.008
- Oxygen- 16.00
Thus the formula mass of each compound
- Cobalt (II) chloride - 129.83
- Cobalt (II) chloride hexahydrate - 262.12
Cobalt (II) chloride hexahydrate decomposes under heat to produce cobalt (II) hexahydrate and water. Hence the equation:
Therefore
- Molar ratio:
- Mass ratio:
The mass ratio indicates that 262.12 grams of cobalt (II) chloride hexahydrate decomposes to produce 129.83 grams of its corresponding anhydrous salt. Accordingly, heating 5.00 grams of the hexahydrate would produce 2.48 grams of its anhydrate.
Answer:
B.
Explanation:
One mole is the amount of substance that contain the Avogadro number which is equal to 6.022×10^23 atom, molecules or ions.
Answer:
Explanation:
N2(g)+O2(g)⇌2NO(g),
N2(g)+2H2(g)⇌N2H4(g),
2H2O(g)⇌2H2(g)+O2(g),
If we add above reaction we will get:
2N2(g)+2H2O(g)⇌2NO(g)+N2H4(g) Eq (1)
Equilibrium constant for Eq (1) is
Divide Eq (1) by 2, it will become:
N2(g)+H2O(g)⇌NO(g)+1/2N2H4(g) Eq (2)
Equilibrium constant for Eq (2) is
I think the correct answer from the choices listed above is the second option. If a mixture of two metals was separated based on one metal's ability to allow electricity to pass, then the property that was important would be conductivity. <span> It is the ability to conduct electricity.</span>
Options are as follow,
A. P₄O₁₀
B. PCl₅
C. Ca₃(PO₄)₂
<span>D. KH</span>₂PO₃
Answer;
The correct option is Option-D (KH₂PO₃).
Explanation:
Oxidation number of Phosphorous is calculated as,
As the normal oxidation number of K is +1, H is +1 and O is -2 so,
KH₂PO₃ = 0
0 shows that the molecule is neutral. Now puttion values of all elemnts except P,
(+1) + (+1)₂ + P + (-2)₃ = 0
+1 + 2 + P - 6 = 0
+3 + P - 6 = 0
+3 + P = +6
P = +6 - 3
P = +3