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Katena32 [7]
3 years ago
13

Question 9 Multiple Choice Worth 4 points)

Chemistry
2 answers:
Rufina [12.5K]3 years ago
4 0

Answer:

A

Explanation:

Would you base your career options using science?

Would you base your moral behavior on science? Science is notorious for not being able to answer moral questions.

Would you base the "meaning of life" on science? The meaning of life is hardly a question that the periodic table could answer.

The only option left is plant growth which science could answer.

Dafna11 [192]3 years ago
3 0

Answer:

plant growth

Explanation:

I got this answer right on a test

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Activities that shows the nature and goals of anthropology,Sociology and Political Science​
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To answer the question effectively, we will talk about the key words in the question.

ANTHROPOLOGY, SOCIOLOGY AND POLITICAL SCIENCE.

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SOCIOLOGY; This is the scientific study of human civilization.

It is systemic and studies of groups and societies that people build

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Sociology greatly focuses on various social connections,

structures, organizations, processes and institutions.

The activities that show the goals and nature of sociology includes;

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5 0
4 years ago
Given that the initial rate constant is 0.0110s−1 at an initial temperature of 21 ∘C , what would the rate constant be at a temp
gulaghasi [49]

The rate constant is mathematically given as

K2=2.67sec^{-1}

<h3>What is the Arrhenius equation?</h3>

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

ln(\frac{K2}{K1})= (\frac{Ea}{R})*(\frac{1}{T1}-\frac{1}{T2})

Therefore

KT1= 0.0110^{-1}

T1= 21+273.15

T1= 294.15K

T2= 200  

T2=200+273.15

T2= 473.15K

Ea= 35.5 Kj/Mol

Hence, in  j/mol R Ea is

Ea=35.5*1000 j/mol R

ln(\frac{K2}{0.0110})= (\frac{35.5*1000}{8.314})*(\frac{1}{294.15}-\frac{1}{473.15}\\\\ln(\frac{K2}{0.0110})=5.492

K2/0.0110 =e^(5.492)

K2/0.0110 =242.74

K2= 242.74*0.0110

K2=2.67sec^{-1}

In conclusion, rate constant

K2=2.67sec^{-1}

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