Answer: There are 0.0637 moles present in 85.0 mL of 0.750 M KOH.
Explanation:
Given: Volume = 85.0 mL (1 mL = 0.001 L) = 0.085 L
Molarity = 0.750 M
It is known that molarity is the number of moles of solute present in liter of a solution.
Therefore, moles present in given solution are calculated as follows.
Thus, we can conclude that there are 0.0637 moles present in 85.0 mL of 0.750 M KOH.
If you have studied enzymes its a similar concept. Cells have proteins on the surface of their cell which hormones bind to (called receptors) The receptor must be a complimentary shape to the hormone for it to bind. Only target cells have the receptor with the complimentary shape so only these cells will be affected.
Answer:
Concentration
Explanation:
Concentration is measure of the quantity of solute present in a given amount of solvent. Concentration can be measured in mol/dm³, g/m³ and other forms like molality, parts per million.
Concentration in mol/dm³(molarity) is a measure of the amount of moles of solute present in 1 dm³ of solvent while concentration in g/dm³ is the number of grams of solute present in 1 dm³ of solvent. These units of concentration can be converted to the other unit by using simple conversion methods.
molality refers to the amount of solute in 1 kg of solvent, while ppm is basically used for very dilute solutions.
Gold is a soft metal. Both malleable and ductile
The answer is 27.7
According to this equation:
q = M C ΔT
When q= the energy that produced when there is a difference in temperature.
M (g) = amount of the material= 1.900 Kg= 1900 g
ΔT= difference in temperature ( in kelvin or C°)= 4.542 K
C= Specific heat capacity=3.21
∴ q = 1900 * 4.542 * 3.21 = 27701.7 J = 27.7 KJ
