Question

A 500 mL piston has a gas mixture inside at a pressure of 15.0 atm. What volume would the piston have if the pressure increased to 30.0 atm?

Answer 1

Answer:

The volume of the piston would be 250 mL.

Explanation:

Volume of the piston, $V_1=500\ mL$

Pressure, $P_1=15\ atm$

Let $V_2$ is the volume of piston if the pressure increased to 30.0 atm.

It is based on Boyle's law. It is given by:

$\dfrac{V_1}{V_2}=\dfrac{P_2}{P_1}\\\\V_2=\dfrac{V_1P_1}{P_2}\\\\V_2=\dfrac{500\times 15}{30}\\\\V_2=250\ mL$

So, the volume of the piston would be 250 mL.