Answer:
the mass required to inflate a 72 L bag is 191.491 g
Explanation:
reaction:
conditions:
- V = 72.0 L
- STP: P = 1 atm ∧ T = 298 K
gas law:
- PV = RTn
- R = 0.082 atm * L / K * mol
⇒ n = PV / RT
⇒ n = ((1 atm) * ( 72.0 L)) / (0.082 atm*L / K*mol) * (298 K)
⇒ n = 2.946 mol
⇒ m = n * Mw = ( 2.946 mol ) * ( 64.99 g/mol)
⇒ m = 191.491 g
Given that the rate of diffusion is 1 mm per 1 second. then the time it travels in 1 cm can be solve using the formula
t = d / r
where d is the distance
r is the rate
first, 1 cm is equal to 10 mm
t = 10 mm / ( 1 mm / s )
t = 10 s
Because despite being natural they still harm the ozone layer and cause breathing problems, even suffocation.
Answer:
a- Uno de carbono y dos de azufre
Explanation:
El compuesto formado entre el carbono y el azufre es CS2.
El carbono forma dos enlaces dobles con dos átomos de azufre.
Por lo tanto, el compuesto contiene un átomo de carbono y dos átomos de azufre.