Which colorless and odorless gas, produced by radioactive decay of uranium-238, is considered to be a form of pollution?

A certain reaction has an activation energy of 28.90 kJ / mol. At what Kelvin temperature will the reaction proceed 5.00 times f

BabaBlast [244]

Answer: 365 K

Explanation:

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

or,

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_1$ = rate constant at $T_1$ = 1.00

$K_2$ = rate constant at $T_2$ = 5.00

$Ea$ = activation energy for the reaction = 28.90 kJ/mol= 28900 j/mol

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = 313 K

$T_2$ = final temperature = ?

Now put all the given values in this formula, we get

$\log (\frac{5.00}{1.00})=\frac{28900}{2.303\times 8.314J/mole.K}[\frac{1}{313K}-\frac{1}{T_2K}]$

$0.69=\frac{28900}{2.303\times 8.314J/mole.K}[\frac{1}{313K}-\frac{1}{T_2K}]$

$T_2=365K$

Therefore, 365 K is required to increase the reaction rate by 5.00 times.

4 0

4 years ago

Fast, slow, why do some reactions occur faster than others?

Liula [17]

Answer:

When the concentration of a reactant increases, there will be more chemical present. Due to more reactant particles moving together, more collisions are allowed to happen and with that, the rate of the reaction is increased. So, the higher the concentration of reactants, the faster the reaction rate will be.

Hope this helped you! :)

3 0

3 years ago

What are the following numbers in scientific notation 0.0006250

wlad13 [49]

First one, 6.250 * 10^(-4). Second one, 9.532 * 10^6. Third one, 4.38904 * 10^5. Forth one, 4.5833 * 10^(-3). The zero before first non-zero number can ignore.

3 0

3 years ago

Charlie is doing a scientific investigation about the properties of light energy. For his experiment, he points a flashlight at

matrenka [14]

Answer:

it would be A.

Explanation:

7 0

3 years ago

Read 2 more answers

write the ground-state electron configurations of the seventh and eighth elements in the first transition series in Universe fif

Tju [1.3M]

Answer: Check explanation.

Explanation:

Transition metals are metallic elements that can be found in the Groups IVB–VIII, IB, and IIB on the periodic chart.

The question require us to write down the GROUND state electronic configuration of the first fifth transition metal, sixth transition metal, seventh transition metal element and the eighth transition metal.

NOTE: we are Starting from Argon, which has 18 electrons.

The fifth transition metal is Manganese,Mn. Manganese has 25 electrons, that is, 25- 18= 7. Therefore, it needs seven electrons to complete the configuration.

Hence, The ground state electronic configuration = [Ar)] 3d5. 4s2.

The first sixth Transition metal is iron,Fe. Iron has 26 electrons, that is, 26 - 18 = 8. Therefore, it need eight Electrons to complete the ground state electronic configuration.

Hence, the ground state electronic configuration of Fe= [Ar] 3d6. 4s2.

The first seventh transition metal is Cobalt, Co. It has 27 Electrons, therefore, 27- 18 = 9. Therefore, it needs 9 Electrons to complete its ground state electronic configuration.

Ground state electronic configuration of Co= [Ar] 3d7. 4s2.

The first eight Transition metal is Nickel. It has 28 electrons. Therefore, 28-18= 10. So, it needs 10 Electrons to complete its ground state electronic configuration.

Hence, the Ground state electronic configuration of Ni= [Ar] 3d8. 4s2.

5 0

3 years ago