Ask question

Ask question

All categories

3 years ago

12

A sample of air has a volume of 140.0 mL at 67C. To w

1 answer:

bonufazy [111]3 years ago

7 0

Answer:

What that means is that when pressure and number of moles are kept constant, increasing the temperature will result in an increase in volume. Likewise, a decrease in temperature will result in a decrease in volume. In your case, the volume of the gas decreased by a factor of about 3, from "140.0 mL" to "50.0 mL".

You might be interested in

The psychoactive drug sold as a methamphetamine - "speed" (c10h15n) - undergoes a series of reactions in the body; the net resul

Phoenix [80]

Answer: The coefficient of nitrogen in the given equation is 2.

Explanation: The reaction for the oxidation of methamphentamine with oxygen gas in the body is given by:

$4C_{10}H_{15}N(s)+55O_2(g)\rightarrow 40CO_2(g)+30H_2O(l)+2N_2(g)$

By Stoichiometry,

4 moles of methamphentamine reacts with 55 moles of oxygen gas to produce 40 moles of carbon dioxide gas, 30 moles of water and 2 moles of nitrogen gas.

Coefficient of $C_{10}H_{15}N=4$

Coefficient of $O_2=55$

Coefficient of $CO_2=40$

Coefficient of $H_2O=30$

Coefficient of $N_2=2$

Hence, the coefficient of nitrogen in the given equation is 2.

8 0

3 years ago

1) What is the name of the following Covalent Compound:<br> N2O6

Mars2501 [29]

Iconic +covalent is the answer to this

8 0

3 years ago

Question 116 g of sunflower oil is

Luba_88 [7]

<h2>Answer: 125.41 mL</h2>

Explanation:

Volume = mass ÷ density

= 116 g ÷ 0.925 g/mL

= 125.41 mL

<h3>A 116 g of sunflower oil of 0.925 g/mL has a volume of 125.41 mL.</h3>

7 0

3 years ago

On a class trip to the coast, you and your lab partner find a rock in the spot marked in red on the diagram. You show your teach

NNADVOKAT [17]

Cause it’s is the same

8 0

3 years ago

Read 2 more answers

If a car is traveling 100 km/h and comes to a stop in 3 minutes,what is acceleration of a passenger who is using vehicle restrai

Rama09 [41]

We are given –

Final velocity of car is, v= 0
Initial velocity of car is, u= 100 km/hr
Time taken, t is = 3 minutes or 180 sec

Here–

$\qquad$ $\pink{\bf \longrightarrow Initial\: velocity = 100 \:km/hr}$

$\qquad$ $\sf \longrightarrow Initial\: velocity = \dfrac{ 100 \times 1000}{3600} \:m/s$

$\qquad$ $\pink{ \bf \longrightarrow Initial\: velocity = 27.78\: m/s}$

Now –

$\qquad$ ____________________________

$\qquad$ $\purple{\bf \longrightarrow Acceleration = \dfrac{Final\: Velocity -Initial \:Velocity }{Time}}$

$\qquad$ $\purple{\bf \longrightarrow Acceleration = \dfrac{v -u}{t}}$

$\qquad$ $\sf \longrightarrow Acceleration = \dfrac{(0- 27.78)}{1800}$

$\qquad$ $\sf \longrightarrow Acceleration =\cancel{ \dfrac{- 27.78}{1800}}$

$\qquad$ $\purple{\bf \longrightarrow Acceleration = -0.15 \: m/s^2}$

$\qquad$ _______________________________

6 0

2 years ago