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BARSIC [14]
3 years ago
10

What are the basic steps in the operation of a solar cell?

Engineering
1 answer:
kati45 [8]3 years ago
7 0

Answer:

Light is absorbed and knocks electrons loose. Loose electrons flow, creating a current. The current is captured and transferred to wires.

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Airbags will deploy in a head on collision but not in a collision that occurs from angle
Aneli [31]

Answer:  

Airbags will deploy in almost any angle.

Explanation:

Cars have sensors around them, so when the car gets hit, the sensors detect a crash and deploy the airbags to keep you safe.

8 0
3 years ago
Line.
Veronika [31]

Air supplied to a pneumatic system is supplied through the C. Actuator

Explanation

Pneumatic systems are like hydraulic systems, it is just that these systems uses compressed air rather than hydraulic fluid.  Pneumatic systems are used widely across the industries. these pneumatic systems needs a constant supply of compressed air to operate. This is provided by an air compressor. The compressor sucks in air at a very high rate from the environment and stores it in a pressurized tank. the Air is supplied thereafter with the help of a actuator valve that is a more sophisticated form of a valve.

From the above statement it is clear that Air supplied to a pneumatic system is supplied through the  Actuator

7 0
4 years ago
A generator operating at 50 Hz delivers 1 pu power to an infinite bus through a transmission circuit in which resistance is igno
olga55 [171]

Answer:

critical clearing angle = 70.3°

Explanation:

Generator operating at = 50 Hz

power delivered = 1 pu

power transferable when there is a fault = 0.5 pu

power transferable before there is a fault = 2.0 pu

power transferable after fault clearance = 1.5 pu

using equal area criterion to determine the critical clearing angle

Attached is the power angle curve diagram and the remaining part of the solution.

The power angle curve is given as

= Pmax sinβ

therefore :  2sinβo = Pm

                   2sinβo = 1

                   sinβo = 0.5 pu

                   βo = sin^{-1} (0.5) = 30⁰

also ;   1.5sinβ1 = 1

               sinβ1 = 1/1.5

               β1 = sin^{-1} (\frac{1}{1.5} ) = 41.81⁰

∴ βmax = 180 - 41.81  = 138.19⁰

attached is the remaining solution

The critical clearing angle = cos^{-1} 0.3372  ≈ 70.3⁰

3 0
3 years ago
What do you push to answer a question in Brainly?
ahrayia [7]

you click the question then it says answer question then u answer it

4 0
3 years ago
Read 2 more answers
E = 50V, R= 1000 ohms, then I =
Margarita [4]

Explanation:

<em>Current</em><em> </em><em>(</em><em>I)</em><em>=</em><em> </em><em><u>Voltage</u></em><em><u> </u></em><em><u>(</u></em><em><u>V)</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>Resistance </em><em>(Ω)</em><em>. </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

<em>I=</em><em> </em><em><u>5</u></em><em><u>0</u></em><em><u>V</u></em>

<em> </em><em> </em><em> </em><em> </em><em>1000</em><em>(Ω)</em>

<em>I=</em><em> </em><em><u>5</u></em><em><u>V</u></em>

<em> </em><em> </em><em> </em><em> </em><em>1</em><em>0</em><em>0</em><em>(Ω)</em>

<em>I=</em><em> </em><em>0</em><em>.</em><em>0</em><em>5</em><em> </em><em>(</em><em>Amp)</em><em>. </em><em>Answer</em>

<em>Voltage=</em><em>V</em>

<em>Current</em><em>=</em><em>I</em>

<em>Resistance</em><em>=</em><em>(Ω)</em><em>. </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(Ω)</em><em>=</em><em>Ohm</em>

<em>And </em><em>SI </em><em>unit</em><em> </em><em>of </em><em>current</em><em> </em><em>is</em><em>. </em><em>Ampere(</em><em>Amp)</em><em> </em>

<em><u>hope</u></em><em><u> this</u></em><em><u> helps</u></em><em><u> you</u></em>

<em><u>have</u></em><em><u> a</u></em><em><u> good</u></em><em><u> day</u></em><em><u>.</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em>

8 0
3 years ago
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