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Alex777 [14]
4 years ago
11

A simple undamped spring-mass system is set into motion from rest by giving it an initial velocity of 100 mm/s. It oscillates wi

th a maximum amplitude of 10 mm. What is its natural frequency?
Engineering
1 answer:
____ [38]4 years ago
6 0

Answer:

f=1.59 Hz

Explanation:

Given that

Simple undamped system means ,system does not consists any damper.If system consists damper then it is damped spring mass system.

Velocity = 100 mm/s

Maximum amplitude = 10 mm

We know that for a simple undamped system spring mass system

V_{max}=\omega A

now by putting the values

V_{max}=\omega A

100 = ω x 10

ω = 10 rad/s

We also know that

ω=2π f

10 = 2 x π x f

f=1.59 Hz

So the natural frequency will be f=1.59 Hz.

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a regular sized microwave will use 850 to 1800 watts depending on the model. An average modern microwave will use around 1200 watts.

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A unidirectional E-Glass fiber-epoxy composite material contains 61% by volume E-Glass fibers stressed under isostrain condition
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Answer:

The total load carried by the fiber will be "98%".

Explanation:

The given values are:

V_{f}=0.61

V_{m}=1-V_{f}

     =1-0.61

     =0.39

E_{f}=10 \ Mpa

\sigma_{f}=0.35 \ Mpa

E_{m}=0.45 \ Mpa , \sigma_{m}=9\times 10^{-3} \ Mpa

As we know,

⇒  E_{e}=fE_{f}+mE_{m}

On putting the estimated values, we get

⇒       =0.61\times 10+0.39\times 0.95

⇒       =6.27 \ Mpa

Now,

⇒  \sigma_{c}=f\sigma_{f}+m\sigma_{m}

On putting the estimated values, we get

⇒       =0.61\times 0.35+0.39\times 0.009

⇒       =0.217 \ Mpa

Therefore,

The load carried by fiber,

=\frac{f\sigma_{f}}{\sigma_{c}}

=\frac{0.35\times 0.61}{0.217}

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The current drawn by fluorescent lighting has a high total harmonic distortion. For this case, THD is calculated to be 88%. The
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Answer:

displacement power factor is 0.959087

Explanation:

given data

THD = 88%

true power factor = 0.72

solution

we get here total harmonic distribution THD is express as here

THD = \sqrt{\frac{1}{g^2}-1}       ..............1

her g is distortion factor

so put here value and we will get g that is

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solve it we get

g = 0.750714

and

displacement power factor is express as

DPF = \frac{PF}{g}   .................2  

put here value and we will get

DPF = \frac{0.72}{0.750714}    

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