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2 years ago

What is the approximate volume of a cylinder with a diameter of 4 cm and I height of 10 cm

Mathematics

2 answers:

andrew-mc [135]2 years ago

6 0

$\pi r^{2} h = \pi 2^{2}(10) = 125.66$ cm

natulia [17]2 years ago

6 0

V≈125.66
V= $\pi$ r²h
r=d/2
So 4/2=2
plug it in
V= $\pi$ 2²*10
V= $\pi$ 40
V≈125.66

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the following data represent the number of people aged 25-64 years covered by health insurance (private or government) in 2018.

astraxan [27]

Answer:

mean = find the total of people in such data by adding up all the totals of people represented by each age then divide that total by 2.

mean = with cumulative or frequency graphs if the numbers range individually like 25-30 and 30-35 etc and so on then you take the midpoint age and multiply it by the frequency number in new column add up both columns then divide by smaller total.

mean = histogram total number of data ie) from 270 people (80 x 0 = 0), (40 x 2 = 0) and so on multiplying the frequency. then add them all up in new column ie) 380 among 270 people = 1.4

mode = histogram highest box

median = histogram add up all data number divided by 2 and can draw this on graph as they sort of are in order ie) 15 to the left and 15 to the right

To find standard deviation you need the copulative formula and the notation change for sample shows the small m and s to represent standard deviation ie) m-n is a notation difference for samples of population's

n = number of scores ie) = 50

Ex = then sum of x = would be the collective total ie) = 270

m = 270/50 = 5.4

Ex^2 = 270 x 270 = 72900 (the square of the total population)

SS = Sum of squares = 72,900 - ( 270^2 / 50) are all the variables.

is the formula = 71,442

the root of SS -1

S^2 = 270 / (50 -1) = 270/49 = 5.51

S = sqrt S^2 = sqrt SS /n-1 = sq rt 50 = and you get your answer here.

Standard Deviation on data example here shown is;

S = sqrt 5.51 = sqrt 71442 / n-1 = sq rt 71442/ 50-1 = sq rt 71442/49 = 38.1837662 from a 270 population that exists with 50 age group 25 -75 to show the ease here and how to remember.

Just retrace and where 270 is change for total

Where 50 is put 64-25 = 39

and where n-1 is put 39-1 and always subtract first before dividing as the formula protects the brackets as seen in bold.

As your very last formula is S = SS/n-1

Step-by-step explanation:

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2 years ago

Each small cube is 1 in³. The length of the large cube is 14 in.

MaRussiya [10]

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3 0

3 years ago

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HELP ASAP

beks73 [17]

D=dollars earned
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(1,5) (2,10) (3,15)

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3 0

3 years ago

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Which property of multiplication is used in the multiplication below?

olasank [31]

Zero property because you are using zeros to multiply

4 0

3 years ago

A motel owner observes that when a room is priced at $60 per day, all 80 rooms of the motel are occupied. For every $3 rise in t

Zinaida [17]

Answer:

a) p(x) = 300 - 3

b) P(x) = -3 x² + 285 x

c) Price of per room per day = $ 157.5

when Number of rooms occupied , x = 47.5

Step-by-step explanation:

Given - A motel owner observes that when a room is priced at $60 per day, all 80 rooms of the motel are occupied. For every $3 rise in the charge per room per day, one more room is vacant. Each occupied room costs an additional $15 per day to maintain.

To find - a) Find the demand function, expressing p, the price charged for each room per day, as a function of x, the number of rooms occupied.

b) Find the profit function P(x).

c) Find the price of per room per day the motel should charge in order to maximize its profit.

Proof -

Let

(x, y) be the point

where x represents number of rooms occupied

and y represents price of room per day.

Now,

Given that,

a room is priced at $60 per day, all 80 rooms of the motel are occupied.

So, point becomes (80, 60)

And given that For every $3 rise in the charge per room per day, one more room is vacant.

So, point becomes (79, 63)

Now, we have two points (80, 60), (79, 63)

Let us assume that,

p(x) be the price charged for each room per day

Now,

By using point - slope formula , we get

p -60 = $\frac{(63 - 60}{(79 - 80)} (x - 80)$

⇒p -60 = (-3)(x-80)

⇒p-60 = 240 -3 x

⇒p(x) = 240 + 60 -3 x

⇒p(x) = 300 - 3 x

Given that,

Each occupied room costs an additional $15 per day to maintain.

Let C(x) be the cost function,

Then C(x) =15 x

now,

Revenue function,

R(x) =x*p

= x*(300 -3 x )

= 300 x - 3 x²

⇒R(x) = 300 x - 3 x²

Now,

We know

Profit function = Revenue function - Cost function

⇒P(x) = R(x)-C(x)

⇒P(x) = (300 x -3 x²) -15 x

⇒P(x) = -3 x² + 285 x

P'(x) = -6 x +285

For Maximize profit , Put P'(x) = 0

⇒-6 x+ 285 =0

⇒6 x= 285

⇒x = $\frac{285}{6}$

⇒x= 47.5

∴ we get

Maximize profit is when price, p = 300 - 3x

= 300 -3(47.5)

= $157.5

⇒Price of per room per day = $ 157.5

when Number of rooms occupied , x = 47.5

5 0

2 years ago