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2 years ago

Draw the isotopic notation for an element with 15 protons, 18 neutrons and 18 electrons

Chemistry

1 answer:

tatiyna2 years ago

5 0

Answer:

can't be done

Explanation:

protons and electrons always are the same number,and the neutrons are found by subtracting the atomic mass and protons/electrons soooooooo it can't have 15 protons, 18 electrons, and 18 neutrons.......i hope this helped if not please tell me.

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The free energy for the oxidation of glucose to CO2 and water is -686 kcal/mol, and the free energy for the reduction of NAD+ to

vitfil [10]

Answer:

Most of free energy available from oxidation of the glucose remains in pyruvate.

Explanation:

The overall reaction of the process glycolysis is:

Glucose + 2 NAD⁺ + 2 ADP + 2 Pi ⇒ 2 Pyruvate + 2 NADH + 2 H⁺ + 2ATP

Glucose is oxidized to give 2 molecules of pyruvate and 2 molecules of NADH and ATP (Energy currency).

<u>Though the free energy of oxidation of glucose is high but only 2 NADH is formed because the most of the free energy that is being released from the oxidation of glucose remains in the pyruvate which is produced in the reaction and thus only 2 molecules are formed.</u>

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3 years ago

What is the molar mass of ethanol (C2H60)?

marin [14]

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2 years ago

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Charlie is balancing an equation. She has identified the atoms and counted the number of each in the reactants and products. Wha

Alecsey [184]

The answer to your question is Coefficients.

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2 years ago

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The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute th

MrRissso [65]

The question is incomplete, complete question is :

The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute the ratio of the reaction rate constants for these two reactions at 25°C.

$\frac{K_1}{K_2}=?$

Activation energy of the reaction 1 , $Ea_1$ = 14.0 kJ/mol

Activation energy of the reaction 2, $Ea_1$ = 11.9 kJ/mol

Answer:

0.4284 is the ratio of the rate constants.

Explanation:

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

The expression used with catalyst and without catalyst is,

$\frac{K_2}{K_1}=\frac{A\times e^{\frac{-Ea_2}{RT}}}{A\times e^{\frac{-Ea_1}{RT}}}$

$\frac{K_2}{K_1}=e^{\frac{Ea_1-Ea_2}{RT}}$

where,

$K_2$ = rate constant reaction -1

$K_1$ = rate constant reaction -2

Activation energy of the reaction 1 , $Ea_1$ = 14.0 kJ/mol = 14,000 J

Activation energy of the reaction 2, $Ea_1$ = 11.9 kJ/mol = 11,900 J

R = gas constant = 8.314 J/ mol K

T = temperature = $25^oC=273+25=298 K$

Now put all the given values in this formula, we get

$\frac{K_1}{K_2}=e^{\frac{11,900- 14,000Jl}{8.314 J/mol K\times 298 K}}=2.3340$

0.4284 is the ratio of the rate constants.

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3 years ago

When gases dissolve in gases or when liquids and gases dissolve in liquids, _________eventually spreads the particles evenly thr

natulia [17]

When gases dissolve in gases or when liquids and gases dissolve in liquids, particles movement eventually spreads the particles evenly throughout the solvent resulting in a homogeneous mixture.

Explanation:

When gases dissolve in gases or when liquids and gases dissolve in liquids, particle movement eventually spreads the particles evenly throughout the solvent resulting in a homogeneous mixture.

Solid particles do not dissolve easily like liquids and gases dissolve. Solid particles when dissolved in solid the particles moves very little. After getting heated and becomes molten then they get mixed.

But in the liquids and gases atoms moves and the particles get eventually spread and also get mixed after cooled.

7 0

3 years ago