All categories

3 years ago

Please help with chemistry work

Chemistry

1 answer:

Andrei [34K]3 years ago

5 0

Answer:

Explanation:

14:

a) Shared pairs = 6

per shared pair between each C-H bond.

and two shared pair between C=C thus total shared pairs are 6

a) Lone pairs = 0

b) Single bonds = 4

Double bonds = 1

Triple bonds = 0

c) Formula = C₂H₄

Name = Ethene

d) Lewis structure = given structure is also Lewis structure.

13:

a) Shared pairs = 3

a) Lone pairs = 2

b) Single bonds = 0

Double bonds = 0

Triple bonds = 1

c) Formula = N₂

Name = Dinitrogen

d) Lewis structure = given structure is also Lewis structure.

You might be interested in

HELPP ME !!!! DUE NOW!!!!!!

Deffense [45]

Answer:

the answer is

Explanation:

hopeit help

8 0

2 years ago

Read 2 more answers

CHEM HELP!

sweet [91]

So let's convert this amount of mL to grams:

$\frac{13.6g}{1mL}*1.2mL=16.32g$

Then we need to convert to moles using the molar weight found on the periodic table for mercury (Hg):

$\frac{1mole}{200.59g}*16.32g=8.135*10^{-2}mol$

Then we need to convert moles to atoms using Avogadro's number:

$\frac{6.022*10^{23}atoms}{1mole} *[8.135*10^{-2}mol]=4.90*10^{22}atoms$

So now we know that in 1.2 mL of liquid mercury, there are $4.90*10^{22}atoms$ present.

4 0

3 years ago

How can you tell that a compound contains an ionic bond

Maurinko [17]

Is this a scienctif question cuss if so it not only helps u with math there’s a lot of subsists like history math English etc....

3 0

2 years ago

Write balanced reactions for the complete combustion of hydrogen. Express your answer as a chemical equation. Identify all of th

Fantom [35]

Answer:

Explanation:

A combustion involves the reaction of a fuel with oxygen (O₂). During the reaction of combustion of hydrogen (H₂), H₂ reacts with O₂ to form water (H₂O). The <em>balanced chemical equation</em> is the following:

2 H₂(g) + O₂(g) → 2 H₂O(g)

According to the chemical equation, 2 moles of H₂O are obtained from the reaction of 2 moles of H₂ with 1 mol of O₂. All reactants and products are in the gaseous phase.

7 0

3 years ago

If aluminum is diffused into a thick slice of silicon with no previous aluminum in it at a temperature of 1100˚C for 8 hours, wh

RideAnS [48]

Answer:

8.354 nanometers

Explanation:

To treat a diffusive process in function of time and distance we need to solve 2nd Ficks Law. This a partial differential equation, with certain condition the solution looks like this:

$\frac{C_{s}-C{x}}{C_{s}-C_{o}}=erf(x/2\sqrt{D*t})$