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3 years ago

Please help with chemistry work

Chemistry

1 answer:

Andrei [34K]3 years ago

5 0

Answer:

Explanation:

14:

a) Shared pairs = 6

per shared pair between each C-H bond.

and two shared pair between C=C thus total shared pairs are 6

a) Lone pairs = 0

b) Single bonds = 4

Double bonds = 1

Triple bonds = 0

c) Formula = C₂H₄

Name = Ethene

d) Lewis structure = given structure is also Lewis structure.

13:

a) Shared pairs = 3

a) Lone pairs = 2

b) Single bonds = 0

Double bonds = 0

Triple bonds = 1

c) Formula = N₂

Name = Dinitrogen

d) Lewis structure = given structure is also Lewis structure.

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Answer:

23.0733 L

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$Mass=\frac {50}{100}\times 125\ g$

Mass = 62.5 g

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The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus, moles are:

$moles= \frac{62.5\ g}{34\ g/mol}$

$moles= 1.8382\ mol$

Consider the given reaction as:

$2H_2O_2_{(aq)}\rightarrow2H_2O_{(l)}+O_2_{(g)}$

2 moles of hydrogen peroxide decomposes to give 1 mole of oxygen gas.

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1 mole of hydrogen peroxide decomposes to give 1/2 mole of oxygen gas.

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1.8382 moles of hydrogen peroxide decomposes to give $\frac {1}{2}\times 1.8382 mole of oxygen gas. Moles of oxygen gas produced = 0.9191 molGiven: Pressure = 746 torr
The conversion of P(torr) to P(atm) is shown below:
[tex]P(torr)=\frac {1}{760}\times P(atm)$

So,

Pressure = 746 / 760 atm = 0.9816 atm

Temperature = 27 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (27 + 273.15) K = 300.15 K

Using ideal gas equation as:

PV=nRT

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P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9816 atm × V = 0.9191 mol × 0.0821 L.atm/K.mol × 300.15 K

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