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Bad White [126]
2 years ago
7

Which factor would be most likely to shirk the size of an atom’s electronic cloud

Chemistry
1 answer:
Vanyuwa [196]2 years ago
7 0

Answer:

positive ion

Forming a positive ion is most likely to shrink the size of an electron cloud because the imbalance of protons causes a greater electrostatic

Explanation:

hope this helps

plz mark brainliest

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Cu + 2AgNO3 → Cu(NO3)2 + 2Ag
Eva8 [605]

Answer:

m_{Ag}=135.8gAg

Y=88.4\%

Explanation:

Hello there!

In this case, according to the described chemical reaction, it is possible to compute the theoretical mass of silver as mass via the 1:2 mole ratio of copper to silver and their atomic mass in the periodic table, in order to perform the following stoichiometric setup:

m_{Ag}=40.gCu*\frac{1molCu}{63.55gCu}*\frac{2molAg}{1molCu}*\frac{107.87gAg}{1molAg}\\\\   m_{Ag}=135.8gAg

Next, given the actual yield of 120 g, we compute the percent yield via:

Y=\frac{120g}{135.8g}*100\%\\\\Y=88.4\%

Regards!

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