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ziro4ka [17]
3 years ago
7

Explain the four quantum numbers

Chemistry
1 answer:
devlian [24]3 years ago
7 0

 Principal (shell) quantum number - n 
 

<span>Describes the energy level in the atom (1 through 7)<span>The maximum number of electrons in n is <span>2n2</span></span></span><span>  </span>
<span>2. Angular (subshell) quantum number - </span>l 
 <span><span>Describes the sublevel in n</span><span>Each energy level has n sublevels</span></span><span>  </span>
<span>3. Magnetic quantum number - </span>m 
 <span><span>Describes the orbital within l</span>s has 1 orbitalp has 3 orbitalsd has 5 orbitalsf has 7 orbitals</span><span>  </span>
<span>4. Spin quantum number - </span>s 
 <span>Describes the spin of the electrons in an orbital.Electrons in the same orbital must have oppisite spins.<span>Possible spins are clockwise or counterclockwise.</span></span>
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3 years ago
Part B Identify the sets of quantum numbers that describe all the electrons in the ground state of a neutral beryllium atom, Be.
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<u>Answer:</u> The set of quantum numbers for the electrons in Be atom are (2, 1, -1, 1/2), (1, 0, 0, 1/2), (1, 0, 0, -1/2) and (2, 0, 0, -1/2)

<u>Explanation:</u>

There are 4 quantum numbers:

  • Principal Quantum number (n) specifies the energy of the electron in a shell.
  • Azimuthal Quantum number (l) specifies the shape of an orbital. The value of it lies in the range of 0 to (n-1)
  • Magnetic Quantum number (m) specifies the orientation of the orbital in space. The value of it lies in the range of -l to +l
  • Spin Quantum number (s) specifies the spin of an electron in an orbital. It can either have a value of +\frac{1}{2} or -\frac{1}{2}

Berylium (Be) is the 4th element of periodic table having electronic configuration of 1s^22s^2

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For first electron:

n=1\\l=0\text{ (for s-subshell)}\\m=0\\s=+\frac{1}{2}

For second electron:

n=1\\l=0\\m=0\\s=-\frac{1}{2}

  • <u>For electrons in 2s-orbital, the quantum numbers can be:</u>

For first electron:

n=2\\l=0\text{ (for s-subshell)}\\m=0\\s=+\frac{1}{2}

For second electron:

n=2\\l=0\text{ (for s-subshell)}\\m=0\\s=-\frac{1}{2}

Hence, the set of quantum numbers for the electrons in Be atom are (2, 1, -1, 1/2), (1, 0, 0, 1/2), (1, 0, 0, -1/2) and (2, 0, 0, -1/2)

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