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Troyanec [42]
3 years ago
12

What is polar and unpolar bonds?

Chemistry
1 answer:
Mars2501 [29]3 years ago
3 0

Answer:Nonpolar bonds form between two atoms that share their electrons equally. Polar bonds form when two bonded atoms share electrons unequally.

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What is the molarity of a solution that contains 25 g of HCl in 150 mL of solution??
Stels [109]
To find molarity 
1) number of mol of solute.
Solute is HCl.
M(HCl)= 1.0+35.5 =36.5 g/mol

25g *1 mol/36.5 g = 25/36.5 mol HCl

2) Molarity is number of mole of the solute in 1 L solution.
150 mL = 0.150 L

(25/36.5 mol HCl )/(0.150 L) = 25/(36.5*0.150) ≈ 4.57≈4.6 mol/L


3 0
3 years ago
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Benzene, C6H8, has an enthalpy of fusion = 10.19 kJ/mol. Calculate the amount of energy which is needed to change 88.0 g of soli
Mandarinka [93]

Answer: About 10,200 Joules of heat is required to transform 80.0 g of solid benzene at 5.53°C into liquid benzene, also at 5.53°C.
5 0
3 years ago
Which electromagnetic wave has the longest wavelength?
Vsevolod [243]
Radio waves has the longest wavelength
7 0
2 years ago
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Which compound is most likely to contain ionic bonds? which compound is most likely to contain ionic bonds? mgf2 ch4 n2o?
AnnyKZ [126]
Answer is: MgF₂, magnesium fluoride.
Magnesium fluoride is salt, ionic compound, because magnesium is metal from 2. group of Periodic table of elements and has low ionisation energy and electronegativity, which means it easily lose valence electons, fluorine is nonmetal with greatest electronegativity, which meand it easily gain electron, so magnesium cation (Mg²⁺) and fluorine anion (F⁻) are formed.
6 0
3 years ago
Gaseous hydrogen iodide is placed in a closed container at 425∘C, where it partially decomposes to hydrogen and iodine: 2HI(g)⇌H
murzikaleks [220]

Answer:

0.0184

Explanation:

Let's consider the following reaction at equilibrium.

2 HI(g) ⇌ H₂(g) + I₂(g)

The concentration equilibrium constant (Kc) is equal to the product of the concentration of the products raised to their  stoichiometric coefficients divided by the product of the concentration of the reactants raised to their  stoichiometric coefficients.

Kc = [H₂] × [I₂] / [HI]²

Kc = (4.78 × 10⁻⁴) × (4.78 × 10⁻⁴) / (3.52 × 10⁻³)²

Kc = 0.0184

5 0
3 years ago
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