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Likurg_2 [28]
3 years ago
12

in bohr's atomic theory when electron moves from one energy level to another energy level more distant from the nucleus energy i

s emitted right?
Physics
1 answer:
Katyanochek1 [597]3 years ago
3 0
No, it is the other way around. When an electron moves from one energy level to another energy level more distant from the nucleus, it gains, not emits energy. The closer it gets to the nucleus, the more energy it emits. If it is far from the nucleus, it gains more energy. 
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You drive a car 1600 ft to the east, then 2500 ft to the north. The trip took 2.5 minutes. What was the magnitude of your averag
elena-14-01-66 [18.8K]

Answer:

Velocity=6.03m/s

Explanation:

Given data

Time t=2.5 minutes=150 seconds

Distance A=1600 ft=487.68 m........east

Distance B=2500 ft=762m ........north

To find

Average velocity

Solution

First we need to find the resultant distance magnitude.To find that we apply Pythagorean theorem to find hypotenuse

So

A^{2}+B^{2}=C^{2}\\  C=\sqrt{A^{2}+B^{2}}\\ C=\sqrt{(487.68m)^{2}+(762m)^{2}}\\ C=904.7m

Velocity=\frac{Distance}{Time}\\Velocity=\frac{904.7m}{150s}\\Velocity=6.03m/s

7 0
3 years ago
In the parallel spring system, the springs are positioned so that the 37 N weight stretches each spring equally. The spring cons
Reptile [31]

Answer:

x = 5.29 m

Explanation:

given,

weight of stretch = 37 N

left-hand spring constant (k₁)= 2.7 N/cm

right hand spring constant(k₂)= 4.3 N/ cm

spring are connected in parallel

F = F₁ + F₂

F = k₁x + k₂x

F = (k₁+ k₂)x

37= (4.3+ 2.7)x

7 x = 37

x = 5.29 m

3 0
3 years ago
Determine the magnitude of the resultant force FR=F1+F2FR=F1+F2. Assume that F1F1F_1 = 235 lblb and F2F2F_2 = 350 lb
Svetlanka [38]

Answer:

<em>585lb</em>

Explanation:

Given the formula for calculating the magnitude of the resultant force as;

F_R = F_1 + F_2

<em>Given </em>

<em></em>F_1 = 235 lb \ and \ F_2 = 350 lb\\F_R = 235lb + 350lb\\F_R = 585lb\\<em></em>

<em>Hence the magnitude of the resultant force is 585lb</em>

4 0
3 years ago
What is the speed of a cyclist that rides west 88 km in 32 minutes?
suter [353]

Answer:

The speed of the cyclist is 2.75 km/min.

Explanation:

Given

  • The distance d = 88 km
  • Time t = 32 minutes

To determine

We need to find the speed of a cyclist.

In order to determine the speed of a cyclist, all we need to do is to divide the distance covered by a cyclist by the time taken to cover the distance.

Using the formula involving speed, time, and distance

s=\frac{d}{t}

where

  • s = speed
  • d = distance covered
  • t = time taken

substitute d = 88, and t = 32 in the formula

s=\frac{d}{t}

s=\frac{88}{32}

Cancel the common factor 8

s=\frac{11}{4}

s=2.75 km/min

Therefore, the speed of the cyclist is 2.75 km/min.

8 0
3 years ago
What determines the amount of energy a substance has
Aleks04 [339]
If you think more specifically about energy,such as thermal energy,the amount of that energy a substance has is determined by the movement of the molecules.hope this helps u
3 0
3 years ago
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