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andrew-mc [135]
3 years ago
12

8. Cart 1 with mass of 2kg moving at +6m/s collides with cart 2 with a mass of 1kg,

Physics
2 answers:
sertanlavr [38]3 years ago
6 0
Around the world around the world
Neko [114]3 years ago
4 0

Answer:its 2kg

Explanation:

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This 200-kg horse ran the track at a speed of 5 m/s. What was the average kinetic energy?
MrRissso [65]

Answer:

<h2>2500 J</h2>

Explanation:

The average kinetic energy can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 200 \times  {5}^{2} \\   = 100 \times 25

We have the final answer is

<h3>2500 J</h3>

Hope this helps you

5 0
3 years ago
A mass on the end of a spring undergoes simple harmonic motion. At the instant when the mass is at its equilibrium position, wha
Paha777 [63]

Answer:

3.At equilibrium, its instantaneous velocity is at maximum

Explanation:

The motion of a mass on the end of a spring is a simple harmonic motion. In a simple harmonic motion, the total mechanical energy of the system is constant, and it is sum of the elastic potential energy (U) and the kinetic energy of the mass (K):

E=U+K=\frac{1}{2}kx^2+\frac{1}{2}mv^2 = const.

where

k is the spring constant

x is the displacement of the spring from equilibrium

m is the mass

v is the speed

As we see from the formula, since the total energy E is constant, when the displacement (x) increases, the speed (v) increases, and viceversa. Therefore, when the mass is at its equilibrium position (which corresponds to x=0), the velocity of the mass will be maximum.

7 0
3 years ago
3. What conclusion can you make about the electric field strength between two parallel plates? Explain your answer referencing P
KIM [24]

Answer:

From the relation above we can conclude that the  as the distance between the two plate increases the electric field strength decreases

Explanation:

I cannot  find any attached photo, but we can proceed anyways theoretically.

The electric field strength (E) at any point in an electric field is the force experienced by a unit positive charge (Q) at that point

i.e

E=\frac{F}{Q}

But the force F

F= \frac{kQ1Q2}{r^2}

But the electric field intensity due to a point charge Q at a distance r meters away is given by

E= \frac{\frac{kQ1Q2}{r^2}}{Q} \\\\\E= \frac{Q1}{4\pi er^2 }

<em>From the relation above we can conclude that the  as the distance between the two plate increases the electric field strength decreases</em>

6 0
3 years ago
object x and y fall from a same height and object x is heavier than y which object would fall faster qnd y​
hjlf

Answer: They’d fall at the same speed, because air resistance is the only thing that makes an object fall faster than another. There’s a video somewhere on the internet of a bowling ball and a feather falling at the same speed in a vacuum, if you look for it. Hope this helps!

4 0
3 years ago
What energy transformations occur in a tv remote?
Tatiana [17]
Pressing the button: Mechanical to electrical 
<span>Waste energy from this step: Mechanical to heat </span>
<span>Converting electrical signal to IR: electrical to electromagnetic (infrared rays) </span>
<span>Waste energy from this step: electrical to heat </span>
<span>Chemical energy from battery: chemical to electrical</span>
6 0
3 years ago
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