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3 years ago

PLZ ANSWER ASAP

Physics

1 answer:

Illusion [34]3 years ago

5 0

Answer:

Option D

48 N

Explanation:

From Newton's law of motion we deduce that the magnitude of force is a product of mass and acceleration hence expressed as, F=ma where F is the magnitude of force, m is the mass of the object and a is the acceleration of the cart. Substituting 24 kg for m and 2 for acceleration then

F=24*2= 48 N

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Which sentences describe the cyclone device?

Yakvenalex [24]

Answer:

✓ A cyclone device accumulates fine particulates from the air by making a dirty air stream flow in a spiral path inside a cylindrical chamber.

✘ It consists of several long and narrow fabric filter bags suspended upside-down in a large enclosure.

✓ When dirty air enters the chamber, the larger particulates strike the chamber wall and fall into a conical dust hopper at the bottom.

✘ Fans blow dirt-filled air upward from the bottom of the enclosure, trapping dirt particles inside the filter bags and releasing clean air from the top.

✓ The top of the chamber has an outlet that lets out cleaned air.

Basically, any of these choices that have the word "filter" are wrong. The point of the cyclone device is to separate the particles without the use of filters. You can tell the right answers based on the picture attached below.

3 0

3 years ago

Read 2 more answers

Two 10-cm-diameter metal plates 1.0 cm apart are charged to {12.5 nC. They are suddenly connected together by a 0.224-mm- diamet

Alekssandra [29.7K]

Answer:

(a).The maximum current in the wire is $4.217\times10^{5}\ A$ .

(b). The electric field in the wire is $11.2\times10^{5}\ N/C$ .

(c).The current also decrease with time.

(d). The total amount of energy dissipated in the wire is $1.126\times10^{-5}\ J$

Explanation:

Given that,

Diameter of metal plates = 10 cm

Distance between the plates = 1.0 cm

Charged = 12.5 nC

Diameter of copper wire = 0.224 mm

We need to calculate the cross section area of the plates

Using formula of area

$A=\pi r^2$

Put the value into the formula

$A=\pi\times(5\times10^{-2})^2$

$A=7.85\times10^{-3}\ m^2$

We need to calculate the capacitor

Using formula of capacitor

$C=\dfrac{\epsilon_{0}A}{d}$

Put the value into the formula

$C=\dfrac{8.85\times10^{-12}\times7.85\times10^{-3}}{1.0\times10^{-2}}$

$C=6.94\times10^{-12}\ F$

We need to calculate the resistance of the wire

Using formula of resistivity

$R=\dfrac{\rho l}{A}$

Put the value into the formula

$R=\dfrac{1.7\times10^{-8}\times1.0\times10^{-2}}{\pi\times(0.1125\times10^{-3})^2}$

$R=4.27\times10^{-3}\ \Omega$

We need to calculate the voltage

Using formula of charge

$q=CV$

$V=\dfrac{q}{C}$

Put the value into the formula

$V=\dfrac{12.5\times10^{-9}}{6.94\times10^{-12}}$

$V=1.801\times10^{3}\ V$

(a). We need to calculate the current

Using formula of current

$I=\dfrac{V}{R}$

$I=\dfrac{1.801\times10^{3}}{4.27\times10^{-3}}$

$I=421779.85\ A$

$I=4.217\times10^{5}\ A$

(b). We need to calculate the electric field

Using formula of electric field

$E=\dfrac{kq}{r^2}$

Put the value into the formula

$E=\dfrac{9\times10^{9}\times12.5\times10^{-9}}{(1.0\times10^{-2})^2}$

$E=11.2\times10^{5}\ N/C$

The electric field in the wire is $11.2\times10^{5}\ N/C$ .

(c). In this case, the voltage between the capacitor plates decreases as the charge decreases with time.

The current is directly proportional to the voltage between the plates .

Hence, The current also decrease with time.

(d). We need to calculate the total amount of energy dissipated in the wire

Using formula of energy

$E=\dfrac{1}{2}CV^2$

Put the value into the formula

$E=\dfrac{1}{2}\times6.94\times10^{-12}\times(1.801\times10^{3})^2$

$E=1.126\times10^{-5}\ J$

The total amount of energy dissipated in the wire is $1.126\times10^{-5}\ J$

Hence, (a).The maximum current in the wire is $4.217\times10^{5}\ A$ .

(b). The electric field in the wire is $11.2\times10^{5}\ N/C$ .

(c).The current also decrease with time.

(d). The total amount of energy dissipated in the wire is $1.126\times10^{-5}\ J$

8 0

3 years ago

Which statement is true regarding the vectors shown.

kap26 [50]

Answer:

Y-> + F-> +G ->=E->

Explanation:

7 0

3 years ago

A car is traveling at 114 m/s and changes its velocity to 77 m/s in 9 sec.

suter [353]

Answer:

Given -

Initial Velocity, u = 114 m/s
Final velocity, v = 77 m/s.
Time taken, t = 9 sec.

To find - 

Acceleration of the car.

Solution -

Here, using the equation of motion v = u + at we can find the acceleration easily.

★ Here,

V = Final velocity
U = Initial Velocity
A = Acceleration
T = Time.

Substituting the values -

→ 77 = 114 + a(9)

→ 9a = 114 - 77

→ 9a = 37

→ a = 37/9

→ a = 4.1 m/s

Therefore, the acceleration of the car will be 4.1 m/s.

5 0

3 years ago

Land masses that move on Earth are called: a. Continents b. Tectonic continents c. Tectonic plates d. Rock Masses

Andrew [12]

Answer:

c. tectonic plates

Explanation:

7 0

4 years ago