Answer:
The number of pounds of cashew is 11
Step-by-step explanation:
Let P represent the peanut
Let C represent the cashew nut.
From question, we were told that Elijah brought a total of 16 pounds of peanuts and cashew nuts. This can be written as:
P + C = 16 (1)
The total cost = $49.50
Cost per peanut = $2.75
Cost per cashew = $3.25
The above can be represented as:
49.50 = 2.75P + 3.25C. (2)
From equation 1,
P + C = 16
P = 16 — C
Substitute the value of P into equation 2:
49.50 = 2.75P + 3.25C.
49.50 = 2.75(16 — C) + 3.25C
49.50 = 44 — 2.75C + 3.25C
49.50 = 44 + 0.5C
Collect like terms
49.50 — 44 = 0.5C
5.5 = 0.5C
Divide both side by 0.5
C = 5.5/0.5
C = 11
Therefore, the number of pounds of cashew is 11
we know that
the volume of a solid oblique pyramid is equal to

where
B is the area of the base
h is the height of the pyramid
in this problem we have that
B is a square

where
<u>
</u>
so


substitute in the formula of volume
![V=\frac{1}{3}*x^{2}*(x+2)\\ \\V=\frac{1}{3}*[x^{3} +2x^{2}]\ cm^{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7D%2Ax%5E%7B2%7D%2A%28x%2B2%29%5C%5C%20%5C%5CV%3D%5Cfrac%7B1%7D%7B3%7D%2A%5Bx%5E%7B3%7D%20%2B2x%5E%7B2%7D%5D%5C%20cm%5E%7B3%7D)
therefore
<u>the answer is</u>
![V=\frac{1}{3}*[x^{3} +2x^{2}]\ cm^{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7D%2A%5Bx%5E%7B3%7D%20%2B2x%5E%7B2%7D%5D%5C%20cm%5E%7B3%7D)
V = (pi)r² h
v = (pi)5² h
v = 25(pi) h
take derivative with respect to h
dv/dh = 25(pi)
(dv/dt)*(dt/dh) = dv/dh
dv/dt is given to be 5 cm³
solved for dv/dh = 25(pi)
5(dt/dh) = 25(pi)
dt/dh = 25(pi)/5
dt/dh = 5(pi)
then the recipricol of dt/dh; we want to find dh/dt = 1/(5(pi))
Answer: Statements 2 and 3
Step-by-step explanation:
On a drawing scale;
1cm - 4m
4CM - 16M (MULTIPLYING BY 4)
6cm - 24m (multiplying by 6)
7cm - 28m (multiplying by 7)
8cm - 32m (multiplying by 8)
9CM - 36M (MULTIPLYING BY 9)