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3 years ago

A circle is cut from a square piece of cloth, as shown:

Mathematics

1 answer:

ra1l [238]3 years ago

4 0

A = 3.14 d= 52
R=52/2 = 26”
A of circle= 3.14 r^2
A=3.14*26^2
A=676(3.14)
A=2,122.64”
So the answer is b

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3x^2 - 4x - 5x^2 + 8x <br> simplify it please

Levart [38]

$3x^2 - 4x - 5x^2 + 8x$

Set up

$-2x^2 + 4x$

Combine like terms

$2x(-x + 2)$

Take out a common factor

$2x(2 - x)$

Rearrange to remove a starting negative coefficient inside the parentheses

The simplification is $\boxed{2x(2 - x)}$ .

3 0

3 years ago

Prove the following trigonometric identities (secx+tanx)(1-sinx/cosx)=1

miss Akunina [59]

Answer:

Below.

Step-by-step explanation:

Convert to sin's and cos's:-

(secx + tanx)(1-sinx)/cosx)

= ( 1/ cos x + sinx / cos x) * ( 1 - sin x )/ cos x)

= (1 + sin x) / cos x) * ( 1 - sin x ) / cos x

= (1 - sin^2 x) / cos^2 x

But 1 - sin^2 x = cos^2 x

so we have

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8 0

3 years ago

24<br> -4?<br> can you help me with this

frez [133]

Answer:

-6

Step-by-step explanation:

24/-4=-6

5 0

3 years ago

Read 2 more answers

What’s the area of the shape

Yuki888 [10]

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3 0

3 years ago

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Homer states that his rocket fell for 14 seconds and estimatesthat the rocket’s altitude was 3000 feet. Use the formula to find

timofeeve [1]

Answer:

The actual distance is 3153.33 ft.

Step-by-step explanation:

The time taken by rocket to fell = 14 seconds.

The altitude of rocket was = 3000 feet.

Since the given time is 14 seconds and with this time we have to calculate the actual height or distance in feet from where the rocket fell.

Use the below formula to find the distance in feet.

$\rm S = \frac{1}{2}at^{2} \\S = Distance \\a = gravitational \ force \\t = time \\S = \frac{1}{2} \times 9.81 \times (14)^{2} \\S = 961.38 \ m \\S = 961.38 \times 3.28ft \\S = 3153.33 \ ft$

Therefore, the actual distance is 3153.33 ft.

4 0

3 years ago