Answer:
There are a total of 2011 integer divisors.
Step-by-step explanation:
The only primes p such that 1/p has finite spaces after the coma are 2 and 5. If we divide a number with last digit odd we will obtain 1 extra digit after the decimal point and if we divide a number by 5 we will obtain 1 more digit if that number has a last digit in the decimal which is not a multiple of 5.
If we take powers of those primes we will obtian one more digit each time. In order to obtain more digits it is convinient to divide by a power of 2 instead of a power of 5, because the resulting number will be smaller.
If we want 2010 digits after the decimal point, we need to divide 1 by 2 a total of 2010 times, hence f(2010) = 2²⁰¹⁰, which has as positive integer divisors every power of 2 between 0 and 2010, hence there are a total of 2011 integer divisors of f(2010).
Answer:
Step-by-step explanation:
The Cartesian Product of two sets is all <u>pairs</u> in which the first element of each pair comes from the first set, and the second element comes from the second set.
This was built using 1 from the first set paired with each number in the second set, then using 2 from the first set paired with each number in the second set, then 13 from the first set paired with each number in the second set.
Bad English! Good solution!
Answer:
BC = 4x-10
Step-by-step explanation:
is the midpoint of AC.
Let the number be Y .
Y is seven
less than 5 times another (let that other be X)
Y=7-5X
sum of both Y and X minus 4 gives one
Y+X-4=1
now solve both equations .
