1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
damaskus [11]
3 years ago
14

In an experiment, shinning which type of light on a strip of metal would be least likely to produce the photoelectric effect?

Chemistry
2 answers:
enot [183]3 years ago
7 0

Answer:

Bright red light.

Explanation:

The light when strikes on an object has the ability to show the photoelectric effect. Different light has different wavelength that determines their photoelectric effects.

The ultraviolet light emit the large amount of energy whereas the redllight emits the least amount of energy. The bright red light is least likely to produce the photoelectric effect.

Thus, the correct answer is option (C).

user100 [1]3 years ago
5 0

C red light isn't an efficient source of light

You might be interested in
Which type of system must exist for chemical equilibrium
larisa86 [58]

Answer: closed system.

Explanation:

4 0
3 years ago
What happens to the motion of molecules when temperature decreases
Juliette [100K]

Answer:

As the temperature of a solid, liquid or gas increases, the particles move more rapidly.

4 0
3 years ago
Read 2 more answers
The following unbalanced equation illustrates the overall reaction by which the body utilizes glucose to produce energy: C6H12O6
s344n2d4d5 [400]

Answer:

the conversion factor is f= 6  mol of glucose/ mol of CO2

Explanation:

First we need to balance the equation:

C6H12O6(s) + O2(g) → CO2(g) + H2O(l) (unbalanced)

C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(l) (balanced)

the conversion factor that allows to calculate the number of moles of CO2 based on moles of glucose is:

f = stoichiometric coefficient of CO2 in balanced reaction / stoichiometric coefficient of glucose in balanced reaction

f = 6 moles of CO2 / 1 mol of glucose = 6  mol of glucose/ mol of CO2

f = 6 mol of CO2/ mol of glucose

for example, for 2 moles of glucose the number of moles of CO2 produced are

n CO2 = f * n gluc = 6 moles of CO2/mol of glucose * 2 moles of glucose= 12 moles of CO2

3 0
4 years ago
Carbon-14 is an isotope used in carbon dating. The nucleus becomes Nitrogen-14 through beta decay. Its half-life is 5370 years.
frosja888 [35]

Answer:

If the half-life of 14C is 5730 years, when this period of time has passed it will have been halved, it is called the exponential decay law of radioactive isotopes.

8 0
3 years ago
Answer the 4 questions pls
Vedmedyk [2.9K]
A b A or just the person above me said
7 0
3 years ago
Read 2 more answers
Other questions:
  • Calculate the partial pressure of the CO2 in the expired air at its peak, assuming 1 atm pressure and a body temperature of 37∘C
    8·1 answer
  • The melting points of canola oil, corn oil, sunflower oil, and peanut oil are 10°C, –11°C, –17°C, and –2°C. If you cool a mixtur
    6·1 answer
  • Match each chemical with the correct use.
    8·2 answers
  • If 100.0g of nitrogen is reacted with 100.0g of hydrogen, what is the theoretical yield of the reaction? What is the excess reac
    12·1 answer
  • Part A Write balanced molecular equation for the reaction between nitric acid and calcium hydroxide. Express your answer as a ch
    5·1 answer
  • CuFeS2 + 3 CuCl2 --> 4 CuCl + FeCl2 + 2 S How many mL of 0.075 M CuCl2 are needed to titrate 0.20 grams of CuFeS2?
    6·1 answer
  • Assuming that a sample of ethanol weighs 560 grams. What is the mass of hydrogen in grams for the sample?
    6·1 answer
  • What type of climate conditions are needed to form coal deposits.
    15·1 answer
  • How many molecules of O2 are present in a 3.90L flask at a temperature of 273K and a pressure of 1.00atm?
    7·2 answers
  • 7. Propane, C₂H₁, has become a popular gas to use in fireplaces.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!