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3 years ago

9

A heterozygous grey elephant is crossed with a homozygous brown elephant

2 answers:

Nesterboy [21]3 years ago

7 0

50% grey 50% brown. You're welcome

Dafna1 [17]3 years ago

4 0

The answer would be 50% gray and 50% brown.

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A toaster changes electrical energy to thermal energy. This is a/an

erastova [34]

A because the toaster converts electrical energy into heat energy and, after the bread has been heated for sufficient time, toasts pop out, ready to be buttered. And converting means transforming.

7 0

3 years ago

IF EARTH HAD NO ATMOSPHERE, WOULD A FALLING OBJECT EVER REACH TERMIONAL VELOCITY?

EleoNora [17]

No. What most people call 'terminal velocity' is the speed of the falling
object when the downward force of gravity is equal to the upward force
of air resistance. At that speed, the vertical forces on the object are
balanced, so it stops accelerating, and falls at a constant speed.

If there were no atmosphere, there would be no upward force due to
air resistance. The falling object would continue to accelerate all the
way down until it went 'splat'.

This is exactly the situation for meteoroids or asteroids falling onto the Moon.

3 0

4 years ago

A solid cylindrical object has a mass of 2.0 kg, a diameter

omeli [17]

Answer:

I = 0.0025 kg.m²

Explanation:

Given that

m= 2 kg

Diameter ,d= 0.1 m

Radius , $R=\dfrac{d}{2}$

$R=\dfrac{0.1}{2}$

R=0.05 m

The moment of inertia of the cylinder about it's axis same as the disc and it is given as

$I=\dfrac{mR^2}{2}$

Now by putting the all values

$I=\dfrac{2\times 0.05^2}{2}$

I = 0.0025 kg.m²

Therefore we can say that the moment of inertia of the cylinder will be 0.0025 kg.m².

4 0

3 years ago

An object is placed a distance of twice the focal length away from a diverging lens. What is the magnification of the image?

Lesechka [4]

Answer:

+1/3

Explanation:

The lens equation states that:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}$

where

f is the focal length

p is the distance of the object from the lens

q is the distance of the image from the lens

For a diverging lens, the focal length is negative: $f=-f$

and we also know that the object is placed a distance of twice the focal length, so $p=2f$

So we can find q from the equation above

$\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-f}-\frac{1}{2f}=-\frac{3}{2f}\\q=-\frac{2}{3}f$

And the magnification of the image is given by

$M=-\frac{q}{p}=-\frac{-\frac{2}{3}f}{2f}=\frac{1}{3}$

5 0

4 years ago

Read 2 more answers

A rocket sled accelerates at a rate of 49.0 m/s2 . Its passenger has a mass of 75.0 kg. (a) Calculate the horizontal component o

Katen [24]

Explanation:

It is given that,

Mass of the passenger, m = 75 kg

Acceleration of the rocket, $a=49\ m/s^2$

(a) The horizontal component of the force the seat exerts against his body is given by using Newton's second law of motion as :

F = m a

$F=75\ kg\times 49\ m/s^2$

F = 3675 N

Ratio, $R=\dfrac{F}{W}$

$R=\dfrac{3675}{75\times 9.8}=5$

So, the ratio between the horizontal force and the weight is 5 : 1.

(b) The magnitude of total force the seat exerts against his body is F' i.e.

$F'=\sqrt{F^2+W^2}$

$F'=\sqrt{(3675)^2+(75\times 9.8)^2}$

F' = 3747.7 N

The direction of force is calculated as :

$\theta=tan^{-1}(\dfrac{W}{F})$

$\theta=tan^{-1}(\dfrac{1}{5})$

$\theta=11.3^{\circ}$

Hence, this is the required solution.

8 0

4 years ago