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dedylja [7]
1 year ago
15

What is the thinnest film (but not zero) that produces a strong reflection for green light with a wavelength of 500 nm ?

Physics
1 answer:
Marizza181 [45]1 year ago
3 0

The thinnest film (but not zero) that produces a strong reflection for green light with a wavelength of 500 nm is <u>200 nm.</u>

<u />

The wavelength of mild, λ = 500 nm

= 500 x 10^-9 m

Refractive index of oil, n1 = 1.25

Refractive index of water, n2 = 1.33

The thickness of the movie, d =?

For a sturdy mirrored image, m = 1

Wavelength, λ= 2 n1 d / m

Thickness, d = λ m / 2 n1

= 500 x 10 -9 * 1 / ( 2 * 1.25 )

= two hundred x 10 -nine m

= 2 hundred nm.

Wavelength is the gap between the same factors (adjacent crests) within the adjacent cycles of a waveform signal propagated in space or alongside a wire. In wireless systems, this duration is usually specified in meters (m), centimeters (cm), or millimeters (mm).

Wavelength may be defined as the space between two successive crests or troughs of a wave. it is measured within the route of the wave.

Wavelength is the distance among two adjacent crests or troughs of a waveform signal propagated in space or along a wire. The wavelength of a wave is usually specified in meters (m), centimeters (cm), or millimeters (mm). The wavelength is inversely related to frequency.

Learn more about Wavelength here brainly.com/question/10750459

#SPJ4

<u />

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A solid nonconducting sphere of radius R has a charge Q uniformly distributed throughout its volume. A Gaussian surface of radiu
anyanavicka [17]

Answer:

1. E x 4πr² = ( Q x r³) / ( R³ x ε₀ )

Explanation:

According to the problem, Q is the charge on the non conducting sphere of radius R. Let ρ be the volume charge density of the non conducting sphere.

As shown in the figure, let r be the radius of the sphere inside the bigger non conducting sphere. Hence, the charge on the sphere of radius r is :

Q₁ = ∫ ρ dV

Here dV is the volume element of sphere of radius r.

Q₁ = ρ x 4π x ∫ r² dr

The limit of integration is from 0 to r as r is less than R.

Q₁ = (4π x ρ x r³ )/3

But volume charge density, ρ = \frac{3Q}{4\pi R^{3} }

So, Q_{1} = \frac{Qr^{3} }{R^{3} }

Applying Gauss law of electrostatics ;

∫ E ds = Q₁/ε₀

Here E is electric field inside the sphere and ds is surface element of sphere of radius r.

Substitute the value of Q₁ in the above equation. Hence,

E x 4πr² = ( Q x r³) / ( R³ x ε₀ )

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