All categories

2 years ago

What is the thinnest film (but not zero) that produces a strong reflection for green light with a wavelength of 500 nm ?

1 answer:

3 0

The thinnest film (but not zero) that produces a strong reflection for green light with a wavelength of 500 nm is <u>200 nm.</u>

<u />

The wavelength of mild, λ = 500 nm

= 500 x 10^-9 m

Refractive index of oil, n1 = 1.25

Refractive index of water, n2 = 1.33

The thickness of the movie, d =?

For a sturdy mirrored image, m = 1

Wavelength, λ= 2 n1 d / m

Thickness, d = λ m / 2 n1

= 500 x 10 -9 * 1 / ( 2 * 1.25 )

= two hundred x 10 -nine m

= 2 hundred nm.

Wavelength is the gap between the same factors (adjacent crests) within the adjacent cycles of a waveform signal propagated in space or alongside a wire. In wireless systems, this duration is usually specified in meters (m), centimeters (cm), or millimeters (mm).

Wavelength may be defined as the space between two successive crests or troughs of a wave. it is measured within the route of the wave.

Wavelength is the distance among two adjacent crests or troughs of a waveform signal propagated in space or along a wire. The wavelength of a wave is usually specified in meters (m), centimeters (cm), or millimeters (mm). The wavelength is inversely related to frequency.

Learn more about Wavelength here brainly.com/question/10750459

#SPJ4

<u />

You might be interested in

Rearranged the equation d=10 v=2.5 for t

eimsori [14]

The time of motion of the object at the given speed and distance is 4 seconds.

<h3>Time of motion of the object</h3>

The time of motion of the object is calculated as follows;

t = d/v

where;

d is distance = 10 m
v is speed = 2.5 m/s
t is time of motion

t = 10/2.5

t = 4 s

Thus, the time of motion of the object at the given speed and distance is 4 seconds.

Learn more about time here: brainly.com/question/2854969

#SPJ1

5 0

2 years ago

A car is running at a velocity of 50 miles per hour and the driver accelerates the car by 10 miles per hour square.How far the c

krek1111 [17]

It will be 80 miles and it can be done only in 16 min

7 0

3 years ago

Read 2 more answers

A crate is dragged up a ramp at constant speed. The work done on the system can be accounted for by:

Alex

Answer:

The work done on the system can be accounted for by;

Both $E_g$ and $E_{int}$

Explanation:

The speed of the crate = Constant

Therefore, the acceleration of the crate = 0 m/s²

The net force applied to the crate, $F_{NET}$ = 0

Therefore, the force of with which the crate is pulled = The force resisting the upward motion of the crate

However, we have;

The force resisting the upward motion of the crate = The weight of the crate + The frictional resistance of the ramp due to the surface contact between the ramp and the crate

The work done on the system = The energy to balance the resisting force = The weight of the crate × The height the crate is raised + The heat generated as internal energy to the system

The weight of the crate × The height the crate is raised = Gravitational Potential Energy = $E_g$

The heat generated as internal energy to the system = $E_{int}$

Therefore;

The work done on the system = $E_g$ + $E_{int}$ .

6 0

3 years ago

The continuous flow of electrons is called ___________.

Brilliant_brown [7]

D. electrical current

4 0

3 years ago

Given two vectors A--> = 4.20 i^+ 7.20 j^ and B--> = 5.70 i^− 2.40 j^ , find the scalar product of the two vectors A-->