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dedylja [7]
2 years ago
15

What is the thinnest film (but not zero) that produces a strong reflection for green light with a wavelength of 500 nm ?

Physics
1 answer:
Marizza181 [45]2 years ago
3 0

The thinnest film (but not zero) that produces a strong reflection for green light with a wavelength of 500 nm is <u>200 nm.</u>

<u />

The wavelength of mild, λ = 500 nm

= 500 x 10^-9 m

Refractive index of oil, n1 = 1.25

Refractive index of water, n2 = 1.33

The thickness of the movie, d =?

For a sturdy mirrored image, m = 1

Wavelength, λ= 2 n1 d / m

Thickness, d = λ m / 2 n1

= 500 x 10 -9 * 1 / ( 2 * 1.25 )

= two hundred x 10 -nine m

= 2 hundred nm.

Wavelength is the gap between the same factors (adjacent crests) within the adjacent cycles of a waveform signal propagated in space or alongside a wire. In wireless systems, this duration is usually specified in meters (m), centimeters (cm), or millimeters (mm).

Wavelength may be defined as the space between two successive crests or troughs of a wave. it is measured within the route of the wave.

Wavelength is the distance among two adjacent crests or troughs of a waveform signal propagated in space or along a wire. The wavelength of a wave is usually specified in meters (m), centimeters (cm), or millimeters (mm). The wavelength is inversely related to frequency.

Learn more about Wavelength here brainly.com/question/10750459

#SPJ4

<u />

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Describe at least two ways that electromagnet force and weak nuclear forces are alike and two ways that they are different.
ruslelena [56]

Different: The weak nuclear force is responsible for radioactive decay within an atom of a substance, while the electromagnetic force causes electrostatic force between charged particles.


Different: The weak force has a very small range of effectiveness (where the force can be felt) while the electromagnetic force has an infinite range.


Same: Both forces act within an nucleus, or on a nuclear level.


Same: The weak nuclear force is mediated by charged particles called bosons, and the electrostatic force is only present within charged objects


The last one may be a bit of a stretch but I hope this helped a bit!

4 0
4 years ago
A star's apparent magnitude is most closely related to which of the following? Select all that apply.
kramer
If you want the "most", then you can't have more than one.

A star's apparent magnitude is determined by both its intrinsic luminosity
and its distance from us.
5 0
3 years ago
Read 2 more answers
Calculate the average speed at 5hrs
Oksanka [162]
Distance/ time = 100/5 = 20 km per hour

The average speed at 5hrs is 20 km per hour.

3 0
2 years ago
Suppose you calculated the speed of light in an unknown substance to be 4.00x10^8 m/s. How could you tell if you made an error i
Mice21 [21]

Answer: You could tell if you made an error in your calculations by repeating the steps.

Speed of light is the fastest/maximum in vacuum which is equal to 3 × 10^8 m/s, therefore speed of light through any material equal to 4 × 10^8 m/s is physically and theoretically impossible and therefore incorrect.

Explanation:

6 0
2 years ago
Consider the circuit shown in the figure to find the power delivered to 6 Ohm resistance (in W). Given that Vs= 30
vekshin1

66.7 Watts

Explanation:

Let R_{1}=1.0 ohms, R_{2}=3.0ohms and R_{3}=6.0\:ohms. Since R_{2} and R_{3} are in parallel, their combined resistance R_{23} is given by

\dfrac{1}{R_{23}}=\dfrac{1}{R_{2}}+\dfrac{1}{R_{3}}

or

R_{23}=\dfrac{R_{2}R_{3}}{R_{2}+ R_{3}}=2.0\:ohms

The total current flowing through the circuit <em>I</em> is given

I=\dfrac{V_{s}}{R_{Total}}

where

R_{Total}=R_{1}+R_{23}= 3.0\:ohms

Therefore, the total current through the circuit is

I=\dfrac{30\:V}{3.0\:ohms}=10\:A

In order to find the voltage drop across the 6-ohm resistor, we first need to find the voltage drop across the 1-ohm resistor V_{1}:

V_{1}=(10\:A)(1.0\:ohms)=10\:V

This means that voltage drop across the 6-ohm resistor V_{3} is 20 V. The power dissipated <em>P</em> by the 6-ohm resitor is given by

P=I^{2}R_{3}= \dfrac{V^{2}}{R_{3}}=\dfrac{(20\:V)^{2}}{6\:ohms}= 66.7 W

4 0
3 years ago
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