Question

Using these coordinates, (3, 1/4) and (-2, -1) write an equation in Point-Slope, Slope-Intercept, and Standard Form.

Answer 1

Answer here$\text{Slope } = \frac{ y_2 - y_1 } { x_2 - x_1 } = \frac{-1 - \frac{1}{4}}{-2 - 3} = \frac{ - \frac{5}{4}}{-5}= \frac{ - \frac{5}{4}\cdot4}{-5\cdot4} =\frac{-5}{ -20} =\boxed{ \bf{ \frac{1}{4}}}$

The slope is 1/4.

The equation in point-slope form is:
y - (-1) = 1/4(x - (-2))
$\boxed{\bf{y + 1 = \frac{1}{4}(x+2)}}$

In slope-intercept form, it is:
y + 1 = 1/4(x+2)
$\boxed{\bf{y = \frac{1}{4}x - \frac{1}{2}}}$

In Standard form it is:
y = 1/4x - 1/2
1/2 = 1/4x - y
Multiply both sides by 4
2 = x - 4y
$\boxed{\bf{x-4y=2}}$

I hope that helps. :)