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2 years ago

A sample of aspirin weighing 5.945 g became contaminated with 2.134 g of sodium sulfate. The resulting

Chemistry

1 answer:

ira [324]2 years ago

7 0

Answer:

The correct answer to the following question will be "62.9 %".

Explanation:

The given values are:

The aspirin's initial amount = 5.945 g.

and is polluted containing 2,134 g of sodium sulfate.

After extraction we provided 3,739 g of pure aspirin.

Now,

$Percentage \ of \ recovery \ aspirin =\frac{Aspirin \ amount \ isolated \ after \ extraction}{initial \ amount \ of \ aspirin}\times 100$

On putting the values in the above formula, we get

⇒ $=\frac{3.739}{5.945}\times 100$

⇒ $=62.9 \ percent$

Note: percent = %

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