Question

A sample of aspirin weighing 5.945 g became contaminated with 2.134 g of sodium sulfate. The resulting

Answer 1

Answer:

The correct answer to the following question will be "62.9 %".

Explanation:

The given values are:

The aspirin's initial amount = 5.945 g.

and is polluted containing 2,134 g of sodium sulfate.

After extraction we provided 3,739 g of pure aspirin.

Now,

$Percentage \ of \ recovery \ aspirin =\frac{Aspirin \ amount \ isolated \ after \ extraction}{initial \ amount \ of \ aspirin}\times 100$

On putting the values in the above formula, we get

⇒                                                    $=\frac{3.739}{5.945}\times 100$

⇒                                                    $=62.9 \ percent$

Note: percent = %