The answer will be 144 because if u had 72 × 2 u would get 11
28)
330.0076
29)
V = l X w X h
V = 12 X 20 X 14
12 X 7 = 84
84 X 2 = 168
168 X 20 = 3360
The volume of the cooler is 3,360 in³
Answer:
b) √200 = 10√2
Step-by-step explanation:
Here, the given expression is: √200
Simplifying the given expression, we get:
200 = 2 x 2 x 2 x 5 x 5
⇒ 200 = (2)² x (5) ² x 2
Taking ROOT both sides, we get:![\sqrt{200} = \sqrt{(2)^{2} \times (5)^{2} \times 2}\\\implies \sqrt{200} = \sqrt{(2)^{2} } \times \sqrt{(5)^{2} } \times \sqrt{(2) } = 2 \times 5 \times \sqrt{2}\\ = 10 \sqrt {2}\\\implies \sqrt{200} = 10 \sqrt {2}](https://tex.z-dn.net/?f=%5Csqrt%7B200%7D%20%20%3D%20%5Csqrt%7B%282%29%5E%7B2%7D%20%20%5Ctimes%20%285%29%5E%7B2%7D%20%20%5Ctimes%20%202%7D%5C%5C%5Cimplies%20%5Csqrt%7B200%7D%20%3D%20%5Csqrt%7B%282%29%5E%7B2%7D%20%7D%20%5Ctimes%20%5Csqrt%7B%285%29%5E%7B2%7D%20%7D%20%5Ctimes%20%20%5Csqrt%7B%282%29%20%7D%20%20%3D%202%20%5Ctimes%205%20%5Ctimes%20%5Csqrt%7B2%7D%5C%5C%20%3D%2010%20%5Csqrt%20%7B2%7D%5C%5C%5Cimplies%20%5Csqrt%7B200%7D%20%20%3D%20%2010%20%5Csqrt%20%7B2%7D)
Hence, √200 = 10√2
Length of the arc = radius x θ = 8 x 45 x π/180
= 8 x π/4 = 2π = 6.28 in ~ 6.3 in