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muminat
3 years ago
10

In a city grid, each block on the east-west streets is 100 meters long. Each block on the north-south streets is 20 meters long.

A walker walks 4 blocks west and then 4 blocks south. How much farther did the walker travel than the actual distance between the start and end points?
Physics
1 answer:
alex41 [277]3 years ago
8 0

Answer:

72.1 m

Explanation:

Hello!

When the walker walks west, each block he walks will be of 100 m, so the walker walked 4*100m = 400 m west.

Similarly, when the walker walks south, he walks 20 meters per block, therefore, the walker walked 4*20 m = 80 m south.

Since the directions west and south are perpendicular, the distance between the start ad end point is:

d = √(400^2 + 80^2) m = 407.92 m

However the walker traveled 480 m

Therefore, the walker traveled 480 - 407.9 m = 72.1 m farther than the actual distance

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A wire 2.80 m in length carries a current of 5.60 A in a region where a uniform magnetic field has a magnitude of 0.300 T. Calcu
Alekssandra [29.7K]

Complete question:

A wire 2.80 m in length carries a current of 5.60 A in a region where a uniform magnetic field has a magnitude of 0.300 T. Calculate the magnitude of the magnetic force on the wire assuming the following angles between the magnetic field and the current.

a) 60 ⁰

b) 90 ⁰

c) 120 ⁰

Answer:

(a) When the angle, θ = 60 ⁰,  force = 4.07 N

(b) When the angle, θ = 90 ⁰,  force = 4.7 N

(c) When the angle, θ = 120 ⁰,  force = 4.07 N

Explanation:

Given;

length of the wire, L = 2.8 m

current carried by the wire, I = 5.6 A

magnitude of the magnetic force, F = 0.3 T

The magnitude of the magnetic force is calculated as follows;

F = BIl \ sin(\theta)

(a) When the angle, θ = 60 ⁰

F = BIl \ sin(\theta)\\\\F = 0.3 \times 5.6 \times 2.8 \times sin(60)\\\\F = 4.07 \ N

(b) When the angle, θ = 90 ⁰

F = BIl \ sin(\theta)\\\\F = 0.3 \times 5.6 \times 2.8 \times sin(90)\\\\F = 4.7 \ N

(c) When the angle, θ = 120 ⁰

F = BIl \ sin(\theta)\\\\F = 0.3 \times 5.6 \times 2.8 \times sin(120)\\\\F = 4.07 \ N

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2 years ago
A point charge of magnitude q is at the center of a cube with sides of length L
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Answer:

Explanation:

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3 years ago
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hammer [34]

Answer:

A step by step to walk

Explanation:

One- Make sure your shoes are tied so that you dont trip

Two- Make sure your way is a cleared path so you dont fall or even hurt yourself

three- use both set of lets to go in any direction you want.

Four- when walking make sure to try and keep a steedy pace so that both set of legs are going up and down but in harmony

3 0
3 years ago
Read 2 more answers
An iron railroad rail is 700 ft long when the temperature is 30°C. What is its length when the temperature is – 10°C?
MAVERICK [17]

Answer:

699.67ft

Explanation:

We are given with,

  • α = 1.2×10⁻⁵ / °C
  • L₀ = 700 ft
  • ΔT = -10°C − 30°C = -40°C

Now, We have to find ΔL:

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Rounded to two significant figures, the change in length is −0.33ft.

<u>Therefore, the final length is approximately 700 ft − 0.33 ft = 699.67ft</u>.

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