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muminat
3 years ago
10

In a city grid, each block on the east-west streets is 100 meters long. Each block on the north-south streets is 20 meters long.

A walker walks 4 blocks west and then 4 blocks south. How much farther did the walker travel than the actual distance between the start and end points?
Physics
1 answer:
alex41 [277]3 years ago
8 0

Answer:

72.1 m

Explanation:

Hello!

When the walker walks west, each block he walks will be of 100 m, so the walker walked 4*100m = 400 m west.

Similarly, when the walker walks south, he walks 20 meters per block, therefore, the walker walked 4*20 m = 80 m south.

Since the directions west and south are perpendicular, the distance between the start ad end point is:

d = √(400^2 + 80^2) m = 407.92 m

However the walker traveled 480 m

Therefore, the walker traveled 480 - 407.9 m = 72.1 m farther than the actual distance

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What is the kinetic energy of a 3-kilogram bali that is rolling at 2 meters per second
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Which type of rays have a wavelength shorter than that of visible light?
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c

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6 0
2 years ago
wo fixed charges, A and B are located at x axis. A is at x = 0 m, B is at x = 4 m. QA = +4.0 μC and QB = -5.0 μC. Calculate the
lys-0071 [83]

Answer:

10250 N/C leftwards

Explanation:

QA = 4 micro Coulomb

QB = - 5 micro Coulomb

AP = 6 m

BP = 2 m

A is origin, B is at 4 m and P is at 6 m .

The electric field due to charge QA at P is EA rightwards

E_{A}=\frac{KQ_{A}}{AP^{2}}=\frac{9\times10^{9}\times4\times10^{-6}}{6^{2}}=1000 N/C (rightwards)

The electric field due to charge QB at P is EB leftwards

E_{B}=\frac{KQ_{B}}{BP^{2}}=\frac{9\times10^{9}\times5\times10^{-6}}{2^{2}}=11250 N/C (leftwards)

The resultant electric field at P due the charges is given by

E = EB - EA

E = 11250 - 1000 = 10250 N/C leftwards

5 0
3 years ago
Density of water 1000kgper m^3 What will be the volume of 3500<br>kg water​
skad [1K]

Answer:

<em>The volume of water is 3.5 cubic meter</em>

Explanation:

<u>Density </u>

The density of a substance or material is the mass per unit volume. The density varies with temperature and pressure.

The formula to calculate the density of a substance of mass (m) and volume (V) is:

\displaystyle \rho=\frac{m}{V}

We are given the density of water as \rho=1,000\ kg/m^3.It's required to find the volume of m=3,500 kg of water. Solving for V:

\displaystyle V=\frac{m}{\rho}

\displaystyle V=\frac{3,500}{1,000}

V=3.5\ m^3

The volume of water is 3.5 cubic meter

5 0
3 years ago
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