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muminat
3 years ago
10

In a city grid, each block on the east-west streets is 100 meters long. Each block on the north-south streets is 20 meters long.

A walker walks 4 blocks west and then 4 blocks south. How much farther did the walker travel than the actual distance between the start and end points?
Physics
1 answer:
alex41 [277]3 years ago
8 0

Answer:

72.1 m

Explanation:

Hello!

When the walker walks west, each block he walks will be of 100 m, so the walker walked 4*100m = 400 m west.

Similarly, when the walker walks south, he walks 20 meters per block, therefore, the walker walked 4*20 m = 80 m south.

Since the directions west and south are perpendicular, the distance between the start ad end point is:

d = √(400^2 + 80^2) m = 407.92 m

However the walker traveled 480 m

Therefore, the walker traveled 480 - 407.9 m = 72.1 m farther than the actual distance

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It took 3.5 hours for a train to travel the distance between two cities at a velocity
Amiraneli [1.4K]

Answer:

420

Explanation:

420 because 120 x 3 = 360

120/2 = 60 and 360 + 60 = 420

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7 0
3 years ago
A series AC circuit contains a resistor, an inductor of 150 mH, a capacitor of 5.00 mF, and a generator with DVmax 5 240 V opera
yanalaym [24]

Given:

Inductance, L = 150 mH

Capacitance, C = 5.00 mF

\Delta V_{max} = 240 V

frequency, f = 50Hz

I_{max} = 100 mA

Solution:

To calculate the parameters of the given circuit series RLC circuit:

angular frequency, \omega =  2\pi f = 2\pi \times50 = 100\pi

a). Inductive reactance,  X_{L} is given by:

\X_{L} = \omega L = 100\pi \times 150\times 10^{-3} = 47.12\Omega

X_{L} = 47.12\Omega 

b). The capacitive reactance,  X_{C} is given by:

\X_{C} = \frac{1}{\omega C} = \frac{1}{2\pi fC} = \frac{1}{2\pi \times 50\times 5.00\times 10^{-3}} = 0.636\Omega

X_{C} = 0.636\Omega

c). Impedance, Z = \frac{\Delta V_{max}}{I_{max}} = \frac{240}{100\times 10^{-3}} = 2400\Omega

Z = 2400\Omega

d). Resistance, R is given by:

Z = \sqrt {R^{2} + (X_{L} - X_{C})}

2400^{2} = R^{2} + (47.12 - 0.636)^{2}

R = \sqrt {5757839.238}

R = 2399.5\Omega

e). Phase angle between current and the generator voltage is given by:

tan\phi = \frac{X_{L} - X_{C}}{R}

\phi =tan^{-1}( \frac{X_{L} - X_{C}}{R})

\phi =tan^{-1}( \frac{47.12 - 0.636}{2399.5}) = tan^{-1}{0.0.01937}

\phi = 1.11^{\circ}

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3 years ago
Oque e um projeto de vida​
zavuch27 [327]

Answer:

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3 years ago
In a circus act, when the tumbling lever is measured, the measurements show that the effort arm is 8 meters long and the resista
Yuki888 [10]

The statement the mechanical advantage of the lever is 16 is False.

<h3>Mechanical Advantage</h3>

Mechanical advantage MA = d/D where

  • d = distance moved by effort and
  • D = distance moved by load

Given that the effort arm is 8 meters long, d = distance moved by effort = 8 m.

Also, given that the resistance arm is 2 meters long, D = distance moved by load = 2 m.

<h3>Calculating the mechanical advantage</h3>

So, substituting the values of the variables into the equation, we have

MA = d/D

MA = 8 m/2 m

MA = 4

Since MA = 4, so, the stament is False.

So, the statement the mechanical advantage of the lever is 16 is False.

Learn more about mechanical advantage here:

brainly.com/question/13779480

3 0
2 years ago
That which flows on uniformly, of which a day is a logical portion, is called time. True or False
mr_godi [17]
The answer to the statement is true because the day is of the logical proportion it has to be time.
3 0
3 years ago
Read 2 more answers
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