The circuit change when a wire is added is, an open circuit occurs and makes all bulbs turn off.
<h3>What is a closed circuit?</h3>
A closed circuit is a type of circuit connection in which the wire connection is complete and current flow occurs, turning the light bulbs on in the process.
<h3>What is an open circuit?</h3>
An open circuit is a type of circuit connection in which the wire connection is incomplete and current cannot flow, turning off the light bulbs.
Thus, the circuit change when the wire is added is, an open circuit occurs and makes all bulbs turn off.
Learn more about open circuit here: brainly.com/question/20351910
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<span>Rising or falling, it does not change.</span>
Answer:
2N
Explanation:
subtract rthe two forces to see which is greater
4-2=2
Answer:
v = 384km/min
Explanation:
In order to calculate the speed of the Hubble space telescope, you first calculate the distance that Hubble travels for one orbit.
You know that 37000 times the orbit of Hubble are 1,280,000,000 km. Then, for one orbit you have:
![d=\frac{1,280,000,000km}{37,000}=34,594.59km](https://tex.z-dn.net/?f=d%3D%5Cfrac%7B1%2C280%2C000%2C000km%7D%7B37%2C000%7D%3D34%2C594.59km)
You know that one orbit is completed by Hubble on 90 min. You use the following formula to calculate the speed:
![v=\frac{d}{t}=\frac{34,594.59km}{90min}=384.38\frac{km}{min}\approx384\frac{km}{min}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bd%7D%7Bt%7D%3D%5Cfrac%7B34%2C594.59km%7D%7B90min%7D%3D384.38%5Cfrac%7Bkm%7D%7Bmin%7D%5Capprox384%5Cfrac%7Bkm%7D%7Bmin%7D)
hence, the speed of the Hubble is approximately 384km/min