All categories

2 years ago

How many different 6- player starting squads can be formed from a volleyball team of 11 players?

1 answer:

7 0

You have to calculate how many combinations of 6 people can be chosen from 11. The formula for this is:
n! / [r! * (n-r)!]
combinations = 11! / [6! * 5!] =
11 * 10 * 9 * 8 * 7 / 5 * 4 * 3 * 2 *1 =
11 * 3 * 2 * 7 =
462 Combinations

Source:
http://www.1728.org/combinat.htm

You might be interested in

What is the median number for the numbers 4, 8, 10, 5, 9

AVprozaik [17]

the answer is 10.

place your index fingers on the 4 & the 9 then move in toward the 10 the number in the middle is 10.

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=1%2F3%20%2812x%20-%2024%29%20%3D%2016" id="TexFormula1" title="1/3 (12x - 24) = 16" alt="1/3 (

coldgirl [10]

1/3(12x-24)=16

3/1[1/3(12x-24)=16]

12x-24=48
+24 +24
12x=72

12x/12=72/12

X=6

4 0

2 years ago

Evaluate (2.4x10^4) (4.5x10^3)

goldfiish [28.3K]

Answer:

108000000x^2

Step-by-step explanation:

6 0

2 years ago

5 1/3 + x = 2 1/2. Use least common denominator or easiest common denominator. Please work out

julia-pushkina [17]

Answer:

The answer is x = -17/6.

Step-by-step explanation:

Given:

5 1/3 + x = 2 1/2 . Using least common denominator.

Now, to solve the equation:

$5\frac{1}{3}+x=2\frac{1}{2}$

$=\frac{16}{3} +x=\frac{5}{2}$

Subtracting both sides from 16/3 we get:

$x=\frac{5}{2}- \frac{16}{3}$

Now, the least common denominator of 2 and 3 is 6.

So, we using this we calculate:

$x=\frac{5\times 3-16\times 2}{6}$

$x=\frac{15-32}{6}$

$x=\frac{-17}{6}$

Therefore, the answer is x = -17/6.

7 0

3 years ago

What expression has the same value of 22+(-32)

Ivahew [28]

Answer:

-10

Step-by-step explanation:

as the -32 is in bracket so we must look at it first. then the (-) is multiplied with the + outside bracket which is +×(-)=- . so it will be plus i.e. 22-32 and final step subtract it. the answer is -10.

4 0

3 years ago