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dexar [7]
3 years ago
12

a car travels 350 miles on 20 gallons of gasoline.how many gallons will be used to travel 875 miles under the same condition? Ex

plain how you did it
Mathematics
1 answer:
Lerok [7]3 years ago
4 0
A car can travel for a distance of 350 miles in = 20 gallons
The car can travel for a distance of 1 mile in = (20/350) gallons
                                                                        = 2/35 gallons
Then
The same car can travel for a distance of 875 miles in = (2/35) * 875 gallons
                                                                                        = 1750/35 gallons
                                                                                        = 50 gallons
So it can be seen that 50 gallons of gasoline is required to travel for a distance of 875 miles. I hope the procedure is clear enough for you to understand.

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The digit 5 appears twice in the number 255,120. How does the total value of the 5 on the right compare to the total value of th
maksim [4K]

Answer:

The value of the first "5" in the number 255,\!120 is ten times that of the second "5\!" in this number.

Step-by-step explanation:

What gives the number "255,\!120" its value? Of course, each of its six digits has contributed. However, their significance are not exactly the same. For example, changing the first \verb!5! to \verb!6! would give 2\mathbf{6}5,\!120 and increase the value of this number by 10,\!000. On the other hand, changing the second \verb!5!\! to \verb!6!\! would give 25\mathbf{6},\!120, which is an increase of only 1,\!000 compared to the original number.

The order of these two digits matter because the number "255,\!120" is written using positional notation. In this notation, the position of each digits gives the digit a unique weight. For example, in 255,\!120\!:

\begin{array}{|r||c|c|c|c|c|c|}\cline{1-7}\verb!Digit!& \verb!2! & \verb!5! & \verb!5! & \verb!1! & \verb!2! & \verb!0!\\\cline{1-7}\textsf{Index} & 5 & 4 & 3 & 2 & 1& 0 \\ \cline{1-7} \textsf{Weight} & 10^{5} & 10^{4} & 10^{3} & 10^{2} & 10^{1} & 10^{0}\\\cline{1-7}\end{array}.

(Note that the index starts at 0 from the right-hand side.)

Using these weights, the value 255,\!120 can be written as the sum:

\begin{aligned}& 255,\!120\\ &= 2 \times 10^{5} + 5 \times 10^{4} + 5 \times 10^{3} + 1 \times 10^{2} + 2 \times 10^{1} + 0 \times 10^{0} \\&=200,\!000 + 50,\!000 + 5,\!000 + 100 + 20 + 0 \end{aligned}.

As seen in this sum, the first "5" contributed 50,\!000 to the total value, while the second "5\!" contributed only 5,\!000.

Hence: The value of the first "5" in the number 255,\!120 is ten times that of the second "5\!" in this number.  

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