The missing choices are:
A. z-score = 92 - 83
B. z-score = (92 - 83)/5
C. z-score = 83 - 92
D. z-score = (92 - 83)/92
The expression she would write to find z-score is z-score =
⇒ B
Step-by-step explanation:
The rule of z-score is z = (x -μ)/σ, where
- x is the score
- μ is the mean
- σ is the standard deviation
The scores of an eighth-grade math test have a normal distribution
∵ The mean is 83
∴ μ = 83
∵ The standard deviation is 5
∴ σ = 5
∵ Din’s test score was 92
∴ x = 92
- Substitute all of these values in the formula of z-score
∴ z-score = ![\frac{92-83}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B92-83%7D%7B5%7D)
The expression she would write to find z-score is z-score = ![\frac{92-83}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B92-83%7D%7B5%7D)
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Answer:
y = -2x - 8
Step-by-step explanation:
<u>Use the point slope form: (y - y1) = m(x - x1)</u>
(y - (-4)) = -2(x - (-2))
y + 4 = -2(x + 2)
y + 4 - 4 = -2x - 4 - 4
y = -2x - 8
Answer: y = -2x - 8
Try this solution:
if given dr/dt=8e^t -e^(2t), then
Answer:
a.
R-------8/38--------RR
R------9/39--------B-------13/38-------RB
G------17/38--------RG
R-------9/38--------BR
B--------13/39------B-------12/38-------BB
G-------17/38-------BG
R-----9/38--------GR
G---------17/39-------B------13/38-------GB
G------16/38-------GG
b).
- 9 ways
- ways you can select 1 blue are; RB,BR,BG,GB
RB=9/39 × 13/38=3/38
BR= 13/39 × 9/38 =3/38
BG= 13/39 × 17/38=17/114
GB= 17/39 × 13/38=17/114
=3/38 +3/38+17/114+ 17/114 =26/57
- Probability of selecting 2 red markers= RR = 9/39 × 8/38 =12/247
- Probability of selecting a green marker and then a red marker= GR= 17/39×9/38 =51/494
Answer:
a) -10 b) 7
Step-by-step explanation:
a) 2(x+ 3) = x - 4
2x + 6 = x - 4
2x - x = -6 - 4
x = -10
b) 4(5x - 2) = 2(9x + 3)
20x - 8 = 18x + 6
20x - 18x = 6 + 8
2x = 14
x = 14/2
x = 7