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tia_tia [17]
3 years ago
13

Describe the results of Ernest Rutherford's gold-foil experiment and explain how his results changed ideas about the distributio

n of positive charge within the atom.
Physics
1 answer:
DochEvi [55]3 years ago
4 0
In Rutherford's gold foil experiment, some of the positive particles would pass through the foil and some would bounce off. This led to a new theory that all of the positive subatomic particles were in the center of the atom instead of evenly spread throughout.
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And this one as well
Serggg [28]
If I'm correct both of the answers are A.
5 0
3 years ago
0.8 mj of energy are used by a blender in 3 and a half minutes what is the power rating on the blender
solong [7]

Answer:

   Power rating on the blender = 3809.52 Watts

Explanation:

   We have expression for power equal to ratio of work and time,

   Energy used by blender = Work done by electricity = 0.8 MJ = 0.8*10^6J=800000J

   Time of using blender = 3.5 minutes = 210 seconds

   So power of blender = 800000/210 = 3809.52 Watts

   Power rating on the blender = 3809.52 Watts

5 0
4 years ago
By what factor does the peak frequency change if the celsius temperature of an object is doubled from 20.0 ∘c to 40.0 ∘c?
mart [117]

Answer:

it increases by a factor 1.07

Explanation:

The peak wavelength of an object is given by Wien's displacement law:

\lambda=\frac{b}{T} (1)

where

b is the Wien's displacement constant

T is the temperature (in Kelvins) of the object

given the relationship between frequency and wavelength of an electromagnetic wave:

f=\frac{c}{\lambda}

where c is the speed of light, we can rewrite (1) as

\frac{c}{f}=\frac{b}{T}\\f=\frac{Tc}{b}

So the peak frequency is directly proportional to the temperature in Kelvin.

In this problem, the temperature of the object changes from

T_1 = 20.0^{\circ}+273=293 K

to

T_2 = 40.0^{\circ}+273 = 313 K

so the peak frequency changes by a factor

\frac{f_2}{f_1} \propto \frac{T_2}{T_1}=\frac{313 K}{293 K}=1.07

8 0
3 years ago
Please help on any part you can. I know it is a lot but any help I’d greatly appreciate. I attempted the problem but still do no
Alika [10]

Answer:

Please help on any part you can. I know it is a lot but any help I’d greatly appreciate. I attempted the problem but still do not understand. Thank you so much!

Explanation:

Please help on any part you can. I know it is a lot but any help I’d greatly appreciate. I attempted the problem but still do not understand. Thank you so much!

\boxed{lol}

7 0
3 years ago
) or<br> The best places to take a pulse are at the radial artery (<br> the carotid artery (
Sergio039 [100]

Answer:

on edge, it is all of them:

carotid

brachial

radial

femoral

popliteal

dorsalis pedis

Explanation:

7 0
3 years ago
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