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Irina18 [472]
3 years ago
12

What is the effect of load resistor on ripple factor

Physics
1 answer:
Zolol [24]3 years ago
7 0
<span>ripple factor can be reduced by increasing the value of the load resistor (which means reducing the load of the circuit)</span>
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Find the velociity of a car which travels 35 m to the right over a period of 40 seconds
GalinKa [24]

Answer:

the velocity of the car is 0.875 m/s

Explanation:

v = d \div t \\ v = 35m \div 40sec = 0.875 \: m \: per \: sec

therefore the V of car is 0.875 m

8 0
3 years ago
For spring break you are traveling to San Diego. The trip is 1,746.4 miles and the trip takes 20.1 hours. How fast will you be t
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Answer:

86 mph

Explanation:

brainliest pls

7 0
3 years ago
A weather balloon holds 2,850 cubic meters of helium. The density of helium is 0.1685 kilograms per cubic meter. How many kilogr
DIA [1.3K]

To answer the specific problem, the balloon contains 480kg of helium. I am hoping that this answer has satisfied your query and it will be able to help you, and if you would like, feel free to ask another question.

3 0
4 years ago
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An airplane flies with a velocity of 55.0 m/s [ 35° N of W] with respect to the air (this is
rodikova [14]

Answer:

21 m/s.  

Explanation:

The computation of the wind velocity is shown below:

But before that, we need to find out the angles between the vectors

53° - 35° = 18°

Now we have to sqaure it i.e given below

v^2 = 55^2 + 40^2 - 2 · 55 · 40 · cos 18°

v^2 = 3025 + 1600 - 2 · 55 · 40 · 0.951

v^2 = 440.6

v = √440.6

v = 20.99

≈ 21 m/s

Hence, The wind velocity is 21 m/s.  

6 0
3 years ago
Air bags are designed to deploy in 10 ms. Given that the air bags expand 20 cm as they deploy, estimate the acceleration of the
joja [24]

As it is given that the air bag deploy in time

t = 10 ms = 0.010 s

total distance moved by the front face of the bag

d = 20 cm = 0.20 m

Now we will use kinematics to find the acceleration

d = v_i*t + \frac{1}{2}at^2

0.20 = 0 + \frac{1}{2}a*0.010^2

0.20 = 5 * 10^{-5}* a

a = 4000 m/s^2

now as we know that

g = 10 m/s^2

so we have

a = 400g

so the acceleration is 400g for the front surface of balloon

3 0
3 years ago
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