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2 years ago

What is the effect of load resistor on ripple factor

1 answer:

7 0

ripple factor can be reduced by increasing the value of the load resistor (which means reducing the load of the circuit)

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Energy can be transformed from one form to another. The diagram shows one such process.

densk [106]

Answer:

chemical to nuclear and radiant

8 0

2 years ago

Read 2 more answers

I need help

musickatia [10]

Answer:

Explanation:

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2 years ago

A bat can detect small objects such as an insect whose size is approximately equal to the wavelength of the sound the bat makes.

slamgirl [31]

Answer:

size of insect = wavelength = 16.1 mm

Explanation:

Since the bat can detect the size of small insects which are of size equal to the wavelength of sound in air

So here we can say that the wavelength of sound is the ratio of speed of sound and its frequency

here we know that

speed of sound in air is 536 m/s

frequency of sound is 33.3 kHz

so here we can say

$\lambda = \frac{v}{f}$

$\lambda = \frac{536}{33.3 \times 10^3}$

$\lambda = 0.0161 m$

$\lambda = 16.1 mm$

7 0

2 years ago

When an automobile moves with constant velocity, the power developed is used to overcome the frictional forces exerted by the ai

geniusboy [140]

Answer:

The total frictional force is 358.0 newtons

Explanation:

Power is the amount of average work (W) an object does on a period of time (Δt):

$P=\frac{W}{\Delta t}$

Remember average work is average force (F) times displacement (Δs):

$P=\frac{F \Delta s}{\Delta t}$

but displacement over time is average speed $v=\frac{\Delta s}{\Delta t}$ , then:

$P=Fv$ (1)

That is, the power of the car is the force the engine does times the speed of the car. As the question states, if the car is at constant velocity then the power developed is used to overcome the frictional forces exerted by the air and the road, that is by Newton's first law, the force the motor of the car does is equal the force of frictional forces. So, to find the frictional forces we only have to solve (1) for F:

$F=\frac{P}{v}$