15.5% by mass is
equivalent 15.5 g urea in 100 g solution or 155 g urea in 1 kg solution. <span>
<span>we know that molality = moles solute / kg solvent
<span>moles solute = 155 g / 60 g/mol = 2.58 moles urea
</span></span></span>
Since there are 155 g
urea in 1000g solution, hence the solvent is 845 g or 0.845 kg
So:<span>
<span>molality = 2.58 / 0.845 = 3.06 m</span></span>
Answer:
its 57.56
Explanation:
dont ask me how it is just is trust me
2CH4 + 2NH3 + 3O2 ---> 2HCN + 6H2O
10g CH4 x 1molCH4/16.042gCH4 x 2mol HCN/2molCH4 = 0.6mol HCN
12g NH3 x 1molNH3/17.034gNH3 x 2molHCN/2molNH3 = 0.7mol HCN
Methane is the limiting reactant
Use the moles of Hydrogen Cyanide that you would get when used the limiting reactant, Methane
0.6molHCN x 27.028gHCN/1molHCN = 16.2grams --> 16 grams Methane
That both of them are warm....at a certain temputurature causing one to fell,cozy