The Coefficients would be:
Hg(CO3)2: 1
AgCl: 4
HgCl4: 1
Ag2CO3: 2
How do we know this?
Because if we look at the coefficent for the first compound, Hg(CO3)2, That means in total we have one Hg and 2 CO3's.
IF the coefficient is 4 for the next compound, AgCl, there are 4 Ag's and 4 Cl's.
Those were the REACTANTS to our equation. Now looking at the arrow, HgCl4 and Ag2CO3 are our PRODUCTS, or, what is FORMED from Hg(CO3)2 and AgCl. So, we need to make sure that they are equal, to obey the law of conservation of mass. So in simpler terms, if we have 4 Cl's on the reactant side, we need 4 on the products side.
So, if we had the coefficient of 1 for HgCl4, this makes sense, because on the products side we had 1 Hg, and 4 Cl's. With the coefficient of 1, we have 1 Hg and 4 Cl's on the products side, as well!
And if we had the coefficient of 2 for Ag2CO3, we would have 4 Ag's total and 2 CO3s, which matches on the reactants side, for we have two CO3's and 4 Ag's.
I hope I could help!
Answer:
Percent ionic character is defined as the ratio of a bond’s actual dipole moment to the dipole moment it would have if the electron were completely transferred from one atom to the other, multiplied by 100
Explanation:
The percent ionic character seeks to establish the amount of electrovalency in a particular compound. It simply compares the covalency i.e extent of shared electrons to the the electrons that are transferred.
It is given as the ratio of the acutal dipole moment to the dipole moment due to ionic character of the bond multiplied by 100:
Percent ionic character = μ_obs/μ_ionic x 100
Where μobs is the actual dipole moment and μ ionic is the dipole moment if the bonds were 100% ionic.
Probably About 2 or 3 more
If you mean chlorate it would be Pb(CLO3)3
If you mean chromate it would be
Pb(CrO4)3
That is approximately .63620 grams.