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Marina86 [1]
2 years ago
9

13.8g element consist 4.6 ×10^22 atoms what is atomic mass of element?​

Chemistry
2 answers:
Keith_Richards [23]2 years ago
8 0
<h2>~<u>Solution</u> :-</h2>
  • Here, to find the atomic mass of element, we must;

We know that,

  • 4.6 x $ \sf{10^{22}}$ atoms of an element weigh 13.8g.

Thus,

The atoms of $ \sf{ 6.02 \times 10^{13}}$ will weigh;

=   \sf{\frac{13.8  \times 6.02 \times  {10}^{23} }{4.6 \times {10}^{22} } } \\

=  \sf{180.6 \: g \:  \: (molar \: mass)}

  • Hence, the molar mass (atomic mass) will be <u>180.6 g.</u>
blondinia [14]2 years ago
5 0

Explanation:

180

1 mole of any substance contains 6.02×10

23

atoms. Thus, 4.6×10

22

atoms corresponds to 0.0764 moles.

0.0764 moles weighs 13.8 g. Thus, 1 mole will weigh 180 g.

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The mineral magnesite contains magnesium carbonate, MgCO3 (molar mass= 84 g/mol), and other impurities. When a 1.26-g sample of
Leviafan [203]

The answer is 33.33 %


The explanation:


According to the reaction equation:


MgCO3(s) + 2HCl (aq) --> MgCl2(aq) + H20(l) + CO2(g)


we can see that 1 mole of MCO3 will produce → 1 mole of CO2


-Now we need o get number of mole of CO2:


and when we have 0.22 g of CO2, so number of mole = mass / molar mass


moles = 0.22 g / 44 g/mol = 0.005 mole


∴ moles of Mg = moles of CO2 = 0.005 mole


∴ mass of Mg = moles * molar mass


= 0.005 * 84 /mol = 0.42 g


∴ Percent of MgCO3 by mass of Mg = 0.42 g / 1.26 * 100


= 33.33 %



6 0
3 years ago
Read 2 more answers
__ Cu + ___ HNO₃ → ___ _Cu(NO₃)₂ + ___ NO₂ + ___ H₂O
ivolga24 [154]

Answer:

Cu + 4HNO3 --->   Cu(NO3)2 + 2NO2 + 2H2O.

Explanation:

Balancing:

Cu + 4HNO3 --->   Cu(NO3)2 + 2 NO2 + 2H2O.

3 0
3 years ago
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Answer:

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Explanation:

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5 0
2 years ago
Suppose you are performing a gas-producing reaction with an unknown metal, X . X ( s ) + 2 H C l ( a q ) ⟶ X C l 2 ( a q ) + H 2
maksim [4K]

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6 0
3 years ago
Rolls of foil are 302 mm wide and 0.018 mm thick. (The density of foil is 2.7 g/cm3 .)
Kruka [31]

Answer:

The length of foil will be 8107.81 cm or 81.7081 m.

Explanation:

Given data:

Width of roll of foil = 302 mm

Height or thickness = 0.018 mm

Density of foil = 2.7 g/cm³

Mass of foil = 1.19 Kg

Length of foil = ?

Solution:

d = m/ v

v = length (l) × width (w) × height (h)

First of we will convert the Kg into gram and mm into cm.

one Kg = 1000 g

1.19 × 1000 = 1190 g

one cm = 10 mm

302 / 10 = 30.2 cm

0.018 / 10 =  0.0018 cm

Now we will put the values in formula:

d = m/ l× h× w

l = m / d × h× w

l = 1190 g / 2.7 g/cm³× 30.2 cm × 0.0018 cm

l = 1190 g/ 0.146772 g/cm

l = 8107.81 cm or 81.7081 m

3 0
3 years ago
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