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We can use the law of conservation of energy to solve the problem.
The total mechanical energy of the system at any moment of the motion is:
where U is the potential energy and K the kinetic energy.
At the beginning of the motion, the ball starts from the ground so its altitude is h=0 and therefore its potential energy U is zero. So, the mechanical energy is just kinetic energy:
When the ball reaches the maximum altitude of its flight, it starts to go down again, so its speed at that moment is zero: v=0. So, its kinetic energy at the top is zero. So the total mechanical energy is just potential energy:
But the mechanical energy must be conserved, Ef=Ei, so we have
and so, the potential energy at the top of the flight is
The total mechanical energy of the system at any moment of the motion is:
where U is the potential energy and K the kinetic energy.
At the beginning of the motion, the ball starts from the ground so its altitude is h=0 and therefore its potential energy U is zero. So, the mechanical energy is just kinetic energy:
When the ball reaches the maximum altitude of its flight, it starts to go down again, so its speed at that moment is zero: v=0. So, its kinetic energy at the top is zero. So the total mechanical energy is just potential energy:
But the mechanical energy must be conserved, Ef=Ei, so we have
and so, the potential energy at the top of the flight is
Answer
given,
current (I) = 16 mA
circumference of the circular loop (S)= 1.90 m
Magnetic field (B)= 0.790 T
S = 2 π r
1.9 = 2 π r
r = 0.3024 m
a) magnetic moment of loop
M= I A
M=
M=
M=
b) torque exerted in the loop
1. Weight is the gravitational pull with which the earth attracts the body towards the center of the earth. The S.I unit is Newton (N)
2. The weight of an object is related to its mass with the below equation.
W = mg
Where W = weight, m = mass and g = acceleration due to gravity
3. The mass m = 50 kg and g = 9.8 m/
Substitute the parameters in the equation above.
W = 50 x 9.8
W = 490 N
4. An object is accelerating when it speeds up. If the object slows down, it means it is decelerating. The correct answer is option A
5. Newton's second law of motion is:
F = ma
Where F = force applied, m = mass and a = acceleration
Therefore, Newton's second law of motion relates an object's acceleration to its net force acting on it. The correct answer is option C
6. According to Newton's second law of motion which relates an object's acceleration to its mass, doubling the net force acting on an object a doubles its acceleration. Because mass is always constant.
7. Since the weight of an object is related to its mass with the equation.
W = mg, If the mass of an object doubles, its weight will also doubles. Option A is the correct answer.
8. If you know the mass of an object, you can calculate its weight with the formula F = mX when X = 9.8m/
9. Force is expressed in unit as Newton (N)
10. The parameters given are :
mass m = 20kg
Force F = 40N
To calculate acceleration, use the formula F = ma
Substitute all the parameters into the equation.
40 = 20a
a = 40/20
a = 2m/
The correct option is D
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