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Trava [24]
3 years ago
12

Q- A body is acted upon by two forces 30N due east and 40N due North. Calculate

Physics
1 answer:
Dmitry_Shevchenko [17]3 years ago
4 0

Answer:

the following image will make you understand

Explanation:

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A student is considering doing a complete repeated measures design experiment involving motor skills. The student's advisor has
Lelu [443]

Answer:

<em>c. ABBA counterbalancing </em>

Explanation:

The student should not use the method because it is a progressive error management technique for each subject by introducing all <em>treatment circumstances twice, first in one sequence, then in the other (AB, BA) by subject counterbalancing.</em>

If participants experience conditions more than once, they experience the conditions first in one order, then the opposite order.

3 0
3 years ago
In which state of matter are particles held together but still able to move around
Aloiza [94]
The answer is B because the water molecules
5 0
3 years ago
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What is the level of incidence
-Dominant- [34]

Answer:

The incidence rate is typically expressed as the number of cases per person-year of observation. Only new cases are considered when computing the incidence rate, while cases that were diagnosed earlier are excluded. The “population at risk” measure is usually obtained from census data.

Explanation:

The incidence rate is typically expressed as the number of cases per person-year of observation. Only new cases are considered when computing the incidence rate, while cases that were diagnosed earlier are excluded. The “population at risk” measure is usually obtained from census data.

5 0
3 years ago
A student woke up in the morning and checked the rain gauge in her backyard. The rain gauge was empty, but the grass was moist.
faust18 [17]
It would most likely be C
Welcome!  :P
5 0
3 years ago
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Two long, parallel wires are attracted to each other by a force per unit length of 350 µN/m. One wire carries a current of 22.5
pishuonlain [190]

Answer

given,

force per unit length = 350 µN/m

current, I = 22.5 A

y = y = 0.420 m

\dfrac{F}{L}= \dfrac{KI_1I_2}{d}

I_2 = \dfrac{F}{L}\dfrac{d}{KI_1}

I_2 = 350\times 10^{-6}\times \dfrac{0.42}{2 \times 10^{-7}\times 22.5}

    I₂ = 32.67 A

distance where the magnetic field is zero

\dfrac{4\pi \times 10^{-7}\times 32.67}{2\pi y_1}=\dfrac{4\pi \times 10^{-7}\times 22.5}{2\pi (0.42-y_1)}

y_1 = 0.248\ m

there the distance at which the magnetic field is zero in the two wire is at 0.248 m.

3 0
3 years ago
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