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Trava [24]
4 years ago
12

Q- A body is acted upon by two forces 30N due east and 40N due North. Calculate

Physics
1 answer:
Dmitry_Shevchenko [17]4 years ago
4 0

Answer:

the following image will make you understand

Explanation:

You might be interested in
What is the distance covered in 20 minutes by a train traveling 500m/m?
MrMuchimi

Answer:

answer is 10km

Explanation:

use "S =Ut "

S=distance U=velocity t =time

no need to convert time into seconds as the velocity has given in meters per minute

3 0
4 years ago
Please help on this one?
nikdorinn [45]

a is the right answer

4 0
3 years ago
Read 2 more answers
A 1325 kg car and a 2050 kg pickup truck approach a curve on a highway that has a radius of 255 m. At what angle should the high
Scorpion4ik [409]

Answer:

the banking angle of the road is 24.2⁰

Explanation:

Given;

speed of the vehicles considered, v = 75 mi/h

Speed in m/s ⇒ 1 mi/h --------> 0.44704 m/s

                         75 mi/h --------> ?

=   75 x 0.44704 m/s = 33.528 m/s

radius of the curve, r = 255 m

The banking angle of the road is calculated as;

\theta = tan^{-1} (\frac{v^2}{rg} )\\\\\theta = tan^{-1} (\frac{33.528^2}{255\times 9.8} )\\\\\theta  = tan^{-1}(0.44983)\\\\\theta  =24.2^0

Therefore, the banking angle of the road is 24.2⁰

8 0
3 years ago
While rowing in a race, John uses his arms to exert a force of 155 N per stroke
Basile [38]

Answer:

Workdone = 2906.25J

Explanation:

Given the following data;

Force, F = 155

Distance, d = 0.75

Stroke, s = 25

Mathematically, work done is given by the formula;

Work done = force * distance * stroke

W = F * d * s

Where,

W is the work done

F represents the force acting on a body.

d represents the distance covered by the body.

s is the number of strokes.

Substituting into the equation, we have;

Workdone = 155*0.75*25

Workdone = 2906.25J

6 0
3 years ago
A particle of mass m=5.00 kilograms is at rest at t=0.00 seconds. a varying force f(t)=6.00t2−4.00t+3.00 is acting on the partic
Agata [3.3K]

Answer:

43 m/s

Explanation:

Mass, m = 5 kg

Force, F(t) = 6t² - 4t + 3

To find the speed, we first need to get the acceleration, a.

Force is the product of mass and acceleration. It is given as:

F = ma

Therefore, acceleration is:

a(t) = F(t)/m

a(t) = (6t² - 4t + 3) / 5

a(t) = 1.2t² - 0.8t + 0.6

Acceleration is the differentiation of velocity with respect to time, t. Therefore, to get velocity, v, we integrate a(t):

a(t) = dv(t) / dt

=> v(t) = (1.2/3)t³ - (0.8/2)t² + 0.6t

v(t) = 0.4t³ - 0.4t² + 0.6t

Therefore, at time t = 5secs, velocity is:

v(5) = 0.4 * (5³) - 0.4 * (5²) + 0.6 * 5

v(5) = 50 - 10 + 3

v(5) = 43 m/s

The velocity at time, t = 5 secs is 43 m/s

8 0
3 years ago
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