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3 years ago

Pollution that enters a water source directly through a pipe or other discharge outlet is called __________ pollution.

2 answers:

6 0

Pollution that enters a water source directly through a pipe or other discharge outlet is called point source pollution.

Leto [7]3 years ago

6 0

The pollution that enters water source directly through a pipe or other discharge outlet is called point source pollution.

Explanation:

The pollution is nothing but the entry of non-soluble materials which harm the environment by disturbing its stability.

The pollution is caused by pollutants which can be classified as point source pollution and non point source pollution.

If the pollutant causing a particular kind of pollution can be identified like wastage through pipe entering the water bodies or chemical wastage from factories are termed as point source pollution and the pollutants which can be identified are termed as non point source pollution.

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In his experiments on "cathode rays" during which he discovered the electron, J.J. Thomson showed that the same beam deflections

Andrews [41]

Answer:

A) his observation is of little importance ,

B) This observation is very important since the movement of the point of light depends on the relationship between the already magnetic electric force

C) see that in this second case it is 4 times less

D) the force of gravity is of the order of 10⁻⁴⁰

therefore it is 10²⁸ times less than the electric force,

Explanation:

A) This observation is of little importance since the cacodylate ray tube always emits electrons, regardless of the material of which it is made.

B) This observation is very important since the movement of the point of light depends on the relationship between the already magnetic electric force

C) the elect's load is 1.6 10⁻¹⁹ C its mass is 9.1 10⁻³¹ kg, let's look for its relation

e / m = 1.6 10⁻¹⁹ / 9.1 10⁻³¹

e / m = 0.1 758 10 10¹² N

look for this in the case of an atom, let's use the lightest atom hydrogen

the homogenize have an electron of charge 1.6 10⁻¹⁹ C

and a mass of 1.6735575 10⁻²⁷ ka

e / M = 1.6 10⁻⁻¹⁹ / 1.67 10⁻²⁷

e / M = 0.96 10⁸ N

We see that in this second case it is 4 times less

D) the force of gravity is of the order of 10⁻⁴⁰

therefore it is 10²⁸ times less than the electric force, therefore it should not contribute to the movement of the light beam

8 0

3 years ago

Intensity: Radiation of a single frequency reaches the upper atmosphere of the earth with an intensity of 1350 W/m2. What is the

sesenic [268]

Answer:

The right answer is "1010 V/m".

Explanation:

The given values are:

Intensity,

$I=1350 \ W/m^2$

$c = 3.00\times 108 \ m/s$

$\mu_0= 4\pi\times 10^{-7} \ T.m/A$

Now,

The electric field's maximum value will be:

= $\sqrt{2\times u\times c\times I}$

On substituting the values in the above formula, we get

= $\sqrt{2\times 4\times \pi\times 10^{-7}\times 3\times 10^8\times 1350}$

= $\sqrt{32400\times 3.14\times 10^{-7}\times 10^8}$

= $1010 \ V/m$

3 0

3 years ago

What can increase the peak emf in an ac generator without changing the frequency?

STatiana [176]

Explanation:

The peak emf in an AC generator is given by :

$\epsilon=NAB\omega$

Here,

N is number of turns in the generator

A is area of the coils

B is magnetic field

$\omega$ is angular frequency

It is clear that the peak emf in an ac generator depends on :

The number of turns in the generator
Area of coils
Magnetic field

8 0

3 years ago

A hollow cylinder of mass 2.00 kg, inner radius 0.100 m, and outer radius 0.200 m is free to rotate without friction around a ho

Aneli [31]

Answer:

h=2.86m

Explanation:

In order to give a quick response to this exercise we will use the equations of conservation of kinetic and potential energy, the equation is given by,

$\Delta PE_i + \Delta KE_i = \Delta PE_f +\Delta KE_f$

There is no kinetic energy in the initial state, nor potential energy in the end,

$mgh+0=0+KE_f$

In the final kinetic energy, the energy contributed by the Inertia must be considered, as well,

$mgh = (\frac{1}{2}mv^2+\frac{1}{2}I\omega^2)$

The inertia of the bodies is given by the equation,

$I=\frac{m(R_1^2+R^2_2)}{2}$

$I=\frac{2(0.2^2+0.1^2)}{2}$

$I=0.05Kgm^2$

On the other hand the angular velocity is given by

$\omega =\frac{v}{R_2}=\frac{4}{1/5} = 2rad/s$

Replacing these values in the equation,

$(0.5)(9.8)(h) =\frac{1}{2}*0.5*4^2+\frac{1}{2}*0.05*20^2$

Solving for h,

$h=2.86m$

5 0

3 years ago

Mrs. Drover is able to see the taxi driver because of the aperture, or

Darya [45]

Mrs. Drover is able to see the taxi driver because of the aperture or also known as opening.
According to the dictionary, aperture means wide opening or gap.
Thus, the answer to this is letter A. OPening.

6 0

4 years ago