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Reil [10]
2 years ago
15

The equilibrium constant for A + 2B → 3C is 2.1 * 10^-6

Chemistry
1 answer:
Mariana [72]2 years ago
7 0

Answer:

b- 4.4 * 10^-12.

Explanation:

Hello.

In this case, as the reaction:

A + 2B → 3C

Has an equilibrium expression of:

K_1=\frac{[C]^3}{[A][B]^2}=2.1x10^{-6}

If we analyze the reaction:

2A + 4B → 6C

Which is twice the initial one, the equilibrium expression is:

K_2=\frac{[C]^6}{[A]^2[B]^4}

It means that the equilibrium constant of the second reaction is equal to the equilibrium constant of the first reaction powered to second power:

K_2=K_1^2

Thus, the equilibrium constant of the second reaction turns out:

K_2=(2.1 * 10^{-6})^2\\\\K_2=4.4x10^{-12}

Therefore, the answer is b- 4.4 * 10^-12.

Best regards.

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3 years ago
A chemist has one solu6on that is 40% sulfuric acid and one that is 10% sulfuric acid. How much of each should she use to make 2
kipiarov [429]

Answer:

12 L of 40% sulfuric acid solution and 8 L of 10% sulfuric acid solution are needed to make 20 L of sulfuric acid solution.

Explanation:

For first solution of sulfuric acid :

C₁ = 40% , V₁ = ?

For second solution of sulfuric acid :

C₂ = 10% , V₂ = ?

For the resultant solution of sulfuric acid:

C₃ = 28% , V₃ = 20L

Also,

<u>V₁ + V₂ = V₃ = 20L</u> ......................................(1)

Using

<u>C₁V₁ + C₂V₂ = C₃V₃</u>

<u>40×V₁ + 10×V₂ = 28×20</u>

So,

40V₁ + 10V₂ = 560........................................(2)

Solving 1 and 2 as:

V₂ = 20 - V₁

Applying in 2

40V₁ + 10(20 - V₁)  = 560

40V₁ + 200 - 10V₁ = 560

30V₁ = 360

<u>V₁ = 12 L</u>

So,

<u>V₂ = 20 - V₁ = 8L</u>

<u><em>12 L of 40% sulfuric acid solution and 8 L of 10% sulfuric acid solution are needed to make 20 L of sulfuric acid solution.</em></u>

4 0
3 years ago
Average Molarity for HCl is .391
Ira Lisetskai [31]

Answer:

#1: 0.00144 mmolHCl/mg Sample

#2: 0.00155 mmolHCl/mg Sample

#3: 0.00153 mmolHCl/mg Sample

Explanation:

A antiacid (weak base) will react with the HCl thus:

Antiacid + HCl → Water + Salt.

In the titration of antiacid, the strong acid (HCl)  is added in excess, and you're titrating with NaOH moles of HCl that doesn't react.

Moles that react are the difference between mmoles of HCl - mmoles NaOH added (mmoles are Molarity×mL added). Thus:

Trial 1: 0.391M×14.00mL - 0.0962M×34.26mL = 2.178 mmoles HCl

Trial 2: 0.391M×14.00mL - 0.0962M×33.48mL = 2.253 mmoles HCl

Trial 3: 0.391M×14.00mL - 0.0962M×33.84mL = 2.219 mmoles HCl

The mass of tablet in mg in the 3 experiments is 1515mg, 1452mg and 1443mg.

Thus, mmoles HCl /mg OF SAMPLE<em> </em>for each trial is:

#1: 2.178mmol / 1515mg

#2: 2.253mmol / 1452mg

#3: 2.219mmol / 1443mg

<h3>#1: 0.00144 mmolHCl/mg Sample</h3><h3>#2: 0.00155 mmolHCl/mg Sample</h3><h3>#3: 0.00153 mmolHCl/mg Sample</h3>
8 0
3 years ago
Why is a saturated NaCl solution an example of an equilibrium system? A. Because of the reversible nature of solidifying and mel
nataly862011 [7]

Answer:

Option B, Because of the reversible nature of crystallizing and dissolving

Explanation:

Solution containing the maximum amount of solute that can be dissolved in the given solvent at the particular temperature is called saturated solution.

Reversible reaction is the reaction which can go in reverse and forward direction both on varying reaction condition.

In the saturated NaCl solution, on lowering temperature, The the dissolved NaCl molecules may crystallize. Likewise on increasing temperature, the crystallized crystals may dissolved. As the reaction moves in both the direction, therefore its considered to be equilibrium system.

Therefore, amog given, option B is correct.

Because of the reversible nature of crystallizing and dissolving

8 0
2 years ago
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