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Licemer1 [7]
3 years ago
11

What 3 mixtures can be separated by filteration

Chemistry
1 answer:
grandymaker [24]3 years ago
7 0
.sand and water
.iron fillings in a liquid
.cereal in milk
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50 extra if correct !!
leva [86]

Answer:

A.

Explanation:

the gradual movement of the continents across the earth's surface through geological time.

7 0
3 years ago
Please show work:<br> Question below
ozzi

Answer:

b) 2.0 mol

Explanation:

Given data:

Number of moles of Ca needed = ?

Number of moles of water present = 4.0 mol

Solution:

Chemical equation:

Ca + 2H₂O     →      Ca(OH)₂ + H₂

now we will compare the moles of Ca and H₂O .

                          H₂O        :        Ca                

                             2           :        1

                             4.0           :       1/2×4.0 = 2.0 mol

Thus, 2 moles of Ca are needed.      

         

3 0
2 years ago
Calculate ΔH∘f for NO(g) at 435 K, assuming that the heat capacities of reactants and products are constant over the temperature
weeeeeb [17]

Answer:

91383 J

Explanation:

The equation of the reaction can be represented as:

\frac{1}{2} N_{2(g)}+\frac{1}{2} O_{2(g)}     ------>NO_{(g)}

Given that:

The standard enthalpy of formation of NO(g) is 91.3 kJ⋅mol−1 at 298.15 K.

The equation below shown the reaction between the enthalpy of reaction at a particular temperature to another.

\delta H^0__{R,T_2} = \delta H^0__{R,T_1} } + \int\limits^{T_2}_{T_1} {\delta C_p(T')} \, dT'

where:

\delta H^0__{R} = enthalpy of reaction

{\delta C_p(T')} = the difference in the heat capacities of the products and the reactants.

∴

\delta H^0__{R,435K} = \delta H^0__{R,298.15K} + \int\limits^{435}_{298.15} {\delta C_p(T')} \, dT'

= 1(91300 J.mol^{-1} ) +\int\limits^{435}_{298.15} [{(29.86)-\frac{1}{2}(29.38)-\frac{1}{2}29.13}]J.K^{-1}.mol^{-1} \, dT'

= 91300 J + (0.605 J.K⁻¹)(435-298.15)K

= 91382.79 J

\delta H^0__{R,435K} ≅ 91383 J

6 0
3 years ago
giving the incomplete equation 2N2O5 (g) which set of products completes and balances the incomplete equarion
a_sh-v [17]

Answer:

The complete question is as follows

Given the incomplete equation: 2 N2O5(g) ==>  Which set of products completes and balances the incomplete equation?

A)2 N2(g) + 3 H2(g)

B)2 N2(g) + 2 O2(g)

C)4 NO2(g) + O2(g)

D)4 NO(g) + SO2(g)

The correct option is C) 4NO2(g) + O2(g)

Explanation:

Note that the products should be NO2 and O2 since the reactant is entirely made up of N and O. option A is not correct as hydrogen cannot emerge as a product in this reaction. Matter can never be created or be destroyed bu can only change in a chemical reaction. Option D is not also correct for the same reason.

Option B is not correct since it did not balance the number of atoms of O and N in the reactant side of the equation.

The option C) 4NO2(g) + O2(g) is therefore the right option since it balances both the elements and the number of atoms of the elements present.

7 0
3 years ago
Write the autoionization reaction for methanol, ch3oh.
aliina [53]
Autoionization Reactions are those reactions in which ions or molecules ionizes spontaneously without adding any external reagent.

For Example,
                    Autoionization of water.

                               H₂O  +  H₂O   ⇆   H₃O⁺  +  OH⁻

Autoionization reaction of Methanol is shown below,

4 0
3 years ago
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