Each of the following substrates can react with a nucleophile in a substitution reaction. Select the substrate that cannot under
go substitution via neighboring group participation (NGP). A B C D
1 answer:
Answer:
Substrate D
Explanation:
In substitution reactions the tertiary substrates cannot undergo substitution via neighboring group participation (NGP) due to the steric impediment, this means that the volume occupied by the substituents is very large and makes it impossible to attack the nucleophile to the substrate carbon.
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Answer:
<em>3.27·10²³ atoms of O</em>
Explanation:
To figure out the amount of oxygen atoms in this sample, we must first evaluate the sample.
The chemical formula for sodium sulfate is <em>Na₂SO₄, </em>and its molar mass is approximately 142.05.
We will use stoichiometry to convert from our mass of <em>Na₂SO₄ </em>to moles of <em>Na₂SO₄</em>, and then from moles of <em>Na₂SO₄ </em>to moles of <em>O </em>using the mole ratio; then finally, we will convert from moles of <em>O </em>to atoms of <em>O </em>using Avogadro's constant.
19.3g <em>Na₂SO₄</em> · ·
·
After doing the math for this dimensional analysis, you should get a quantity of approximately <em>3.27·10²³ atoms of O</em>.
Answer:
81.3 %
Explanation:
The formula for the calculation of moles is shown below:
For ferrocene:-
Mass of ferrocene = 100 mg = 0.1 g
Molar mass of ferrocene = 186.04 g/mol
The formula for the calculation of moles is shown below:
Thus,
For acetyl chloride:-
Volume = 40 microliters = 0.04 mL
Density = 1.1 g / mL
Density is defined as:-
or,
Mass of acetyl chloride = 0.044 g
Molar mass of acetyl chloride = 78.49 g/mol
The formula for the calculation of moles is shown below:
Thus,
As per the reaction stoichiometry, one mole of ferrocene reacts with one mole of acetyl chloride to give one mole of monoacetylferrocene
Limiting reagent is the one which is present in small amount. Thus, ferrocene is limiting reagent.
The formation of the product is governed by the limiting reagent. So,
one mole of ferrocene on reaction forms one mole of monoacetylferrocene
0.0005375 mole of ferrocene on reaction forms 0.0005375 mole of monoacetylferrocene
Moles of product formed = 0.0005375 moles
Molar mass of monoacetylferrocene = 228.07 g/mole
Mass of monoacetylferrocene produced = Moles*molecular weight = 0.0005375*228.07 g = 0.123 grams = 123 mg
Given experimental yield = 100 mg
<u>% yield = (Experimental yield / Theoretical yield) × 100 = (100/ 123) × 100 = 81.3 %</u>