Each of the following substrates can react with a nucleophile in a substitution reaction. Select the substrate that cannot under
go substitution via neighboring group participation (NGP). A B C D
1 answer:
Answer:
Substrate D
Explanation:
In substitution reactions the tertiary substrates cannot undergo substitution via neighboring group participation (NGP) due to the steric impediment, this means that the volume occupied by the substituents is very large and makes it impossible to attack the nucleophile to the substrate carbon.
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The question is incomplete, here is the complete question:
An aqeous solution of oxalic acid was prepared by dissolving a 0.5842 g of solute in enough water to make a 100 ml solution a 10 ml aliquot of this solution was then transferred to a volumetric flask and diluted to a final volume of 250 ml. How many grams of oxalic acid are in 100. mL of the final solution?
<u>Answer:</u> The mass of oxalic acid in final solution is 0.0234 grams
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
......(1)
Given mass of oxalic acid = 0.5842 g
Molar mass of oxalic acid = 90 g/mol
Volume of solution = 100 mL
Putting values in equation 1, we get:
To calculate the molarity of the diluted solution, we use the equation:
where,
are the molarity and volume of the concentrated oxalic acid solution
are the molarity and volume of diluted oxalic acid solution
We are given:
Putting values in above equation, we get:
Now, calculating the mass of glucose by using equation 1, we get:
Molarity of oxalic acid solution = 0.0026 M
Molar mass of oxalic acid = 90 g/mol
Volume of solution = 100 mL
Putting values in equation 1, we get:
Hence, the mass of oxalic acid in final solution is 0.0234 grams