Answer:
The composition of 1-propanol in vapor phase = 11.54 %
The composition of 2-propanol in vapor phase = 88.46 %
Explanation:
Mole fraction of components in liquid phase:
1-propanol = 
2-propanol = 

Partial pressure of 1-propanol =
Partial pressure of 2-propanol =
According to Raoults law:


Mole fraction of components in vapor phase:
1-propanol = 

The composition of 1-propanol in vapor phase:
100 × 0.1154= 11.54 %
2-propanol = 

The composition of 2-propanol in vapor phase:
100 × 0.8846 = 88.46 %