Answer:
11.1 cm
Explanation:
Let d be the depth upto which box dipped into water.
Volume of water displaced
.12\times .12\times d m^3\\
=.0144d
Weight of water displaced = upthrust
=.0144d\times 10^3\times g\\ [ density of water is 1000kg /m³]
=14.4dg This will act upwards.
Total downward force = 1.2 +.4 = 1.6 g
For equilibrium
1.6g = 14.4 gd
d = .111 m
=11.1 cm.
Answer:
Explanation:
I guess we are ASSUMING that this is a rear wheel drive car as a front wheel drive car will never get the front wheel normal force to zero
If we consider it as a statics problem and choose our moment center carefully...say 0.7 m above the rear wheel to ground contact point.
Call the traction force at the rear wheels F
The normal force on the front wheels will be zero, so no moment generated by the front wheels.
Summing moments about our chosen point to zero
1600(9.8)[2.6 / 2] - F[0.7] = 0
F = 291,200
this force will create an acceleration of
a = F/m
a = 291200/1600
a = 182 m/s²
which is about 18.6 times gravity acceleration
Answer:
1.84 m from the initial point (3.16 m from the ceiling)
Explanation:
According to the law of conservation of energy, the initial kinetic energy of the ball will be converted into gravitational potential energy at the point of maximum height.
Therefore, we can write:
where
m = 2 kg is the mass of the ball
v = 6 m/s is the initial speed of the ball
g = 9.8 m/s^2 is the acceleration due to gravity
is the change in height of the ball
Solving for ,
So, the ball raises 1.84 compared to its initial height.
Therefore:
- if we take the initial position of the ball as reference point, its maximum height is at 1.84 m
- if we take the ceiling as reference point, the maximum height of the ball will be
5 m - 1.84 m = 3.16 m from the ceiling
