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EastWind [94]
3 years ago
11

HELP. LOOK AT THE PICTURE

Mathematics
1 answer:
Lena [83]3 years ago
7 0

Answer:

B

Step-by-step explanation:

Since the person used >200 kWh that month, you would use the bottom equation: 0.15(x-200)+20.

(BTW, the x>200 or x≤200 means if they used more or less than/equal to 200 hours)

From there, you can plug in the number of hours for x, which is 400. So, 0.15([400]-200)+20

0.15(200)+20

30+20

50

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What's the answer to this math problem
GarryVolchara [31]
Total number of marbles:
75 + 50 + 100 + 25 = 250

Probability of selecting a red marble:
25/250 (since 25 out of 250 marbles are red)
Since the top and bottom of this fraction are both divisible by 25, we can go ahead and divide them both by 25, simplifying to 1/10.

Probability of selecting a green marble:
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Simplifies to 2/10
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Probability of selecting a blue or orange marble
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To find the probability that each event occurs in order, simply multiply them all together.

\frac{1}{10}\times\frac{1}{5}\times\frac{7}{10}=\frac{1\times1\times7}{10\times5\times10}=\boxed{\frac{7}{500}}
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3 years ago
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Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n
aliya0001 [1]

Answer:

f(x)=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}

Step-by-step explanation:

The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by

f(x)=f(0)+f^{\prime}(0)x+f^{\prime \prime}(0)\dfrac{x^2}{2!}+ ...+f^{(n)}(0)\dfrac{x^n}{n!}+...

We first compute the n-th derivative of f(x)=\ln(1+2x), note that

f^{\prime}(x)= 2 \cdot (1+2x)^{-1}\\f^{\prime \prime}(x)= 2^2\cdot (-1) \cdot (1+2x)^{-2}\\f^{\prime \prime}(x)= 2^3\cdot (-1)^2\cdot 2 \cdot (1+2x)^{-3}\\...\\\\f^{n}(x)= 2^n\cdot (-1)^{(n-1)}\cdot (n-1)! \cdot (1+2x)^{-n}\\

Now, if we compute the n-th derivative at 0 we get

f(0)=\ln(1+2\cdot 0)=\ln(1)=0\\\\f^{\prime}(0)=2 \cdot 1 =2\\\\f^{(2)}(0)=2^{2}\cdot(-1)\\\\f^{(3)}(0)=2^{3}\cdot (-1)^2\cdot 2\\\\...\\\\f^{(n)}(0)=2^n\cdot(-1)^{(n-1)}\cdot (n-1)!

and so the Maclaurin series for f(x)=ln(1+2x) is given by

f(x)=0+2x-2^2\dfrac{x^2}{2!}+2^3\cdot 2! \dfrac{x^3}{3!}+...+(-1)^{(n-1)}(n-1)!\cdot 2^n\dfrac{x^n}{n!}+...\\\\= 0 + 2x -2^2  \dfrac{x^2}{2!}+2^3\dfrac{x^3}{3!}+...+(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}+...\\\\=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^n\dfrac{x^n}{n}

3 0
3 years ago
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bixtya [17]

Answer:

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Step-by-step explanation:

Combination is the number of ways to select <em>k</em> items from <em>n</em> distinct items when the order of selection does not matters.

Whereas permutation is the number of ways to select <em>k</em> item from <em>n</em> items when order of selection matters.

The number of people entering this year is 22.

The number of ways to select 5 people for Grand Prize is, {22\choose 5}=\frac{22!}{5!(22-5)!} =26334.

The remaining number of people is, 22 - 5 = 17.

It is provided that the other 5 are selected according to an order.

The number of ways to select other 5 winners is,

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The total number of ways to select 10 winners of 22 is:

Total number of ways = 26334 × 742560 = 19,554,575,040.

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